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Chemistry: Post your doubts here!

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one more question :)
how to differentiate between permanent and induced dipoles ...i know that in permanent there is a difference in the electronegativities ..but how to know which have the higher electronegativity?
 
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one more question :)
how to differentiate between permanent and induced dipoles ...i know that in permanent there is a difference in the electronegativities ..but how to know which have the higher electronegativity?
the difernce in the + and the - charge .higher the dfrnce higher the electronegativity
 
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On collision, airbags in cars inflate rapidly due to the production of nitrogen.
The nitrogen is formed according to the following equations.
2NaN3----->2Na+3N2
10Na+2KNO3----->K2O+5Na2O+N2
How many moles of nitrogen gas are produced from 1 mol of sodium azide?
A 1.5 B 1.6 C 3.2 D 4.0


hows it B?
 
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please help me with Q20 with explanation.
Well the molecule is a cis-molecule so its either A or C
it has a formula of C20H28O, which is also CnH2n-12O. It has some double bonds, an aldehyde group and a cyclohexene ring
Lets start of with an alkane and change it into the molecule in question
An alkane has a formula of CnH2n+2
If you could change it into an aldehyde, you lose 2hydrogens and gain one Oxygen
so now its CnH2nO
If you could make part of it into a ring, adding a cyclohexane ring, you reduce number of hydrogens by 2. Noticed I added cyclohexane isntead of cyclohexene. We'll take care of double bonds later
now its CnH2n-2O
So now the only group we haven't considered is alkene. Each alkene reduces the H number by 2, so if there are 5 alkenes,
the formula would be CnH2n-12O, which is our molecule

So answer is A

EDIT: Fixed up some mistakes, you should reread it if you read it already
 
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On collision, airbags in cars inflate rapidly due to the production of nitrogen.
The nitrogen is formed according to the following equations.
2NaN3----->2Na+3N2
10Na+2KNO3----->K2O+5Na2O+N2
How many moles of nitrogen gas are produced from 1 mol of sodium azide?
A 1.5 B 1.6 C 3.2 D 4.0


hows it B?

1 moll of NaN3 produces 1.5N2 according 2 equation....but it also produces 1 mol Na which gives 0.1mol of N2 so in total it is 1.6mol of N2
 
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Well the molecule is a cis-molecule so its either A or C
it has a formula of C20H28O, which is also CnH2n-12O. It has some double bonds, an aldehyde group and a cyclohexene ring
Lets start of with an alkane and change it into the molecule in question
An alkane has a formula of CnH2n+2
If you could change it into an aldehyde, you lose 2hydrogens and gain one Oxygen
so now its CnH2nO
If you could make part of it into a ring, adding a cyclohexane ring, you reduce number of hydrogens by 2. Noticed I added cyclohexane isntead of cyclohexene. We'll take care of double bonds later
now its CnH2n-2O
So now the only group we haven't considered is alkene. Each alkene reduces the H number by 2, so if there are 5 alkenes,
the formula would be CnH2n-12O, which is our molecule

So answer is A

EDIT: Fixed up some mistakes, you should reread it if you read it already

Thanks! You saved my grade! :)
 
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