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Can someone explain the answers of C(i) and C(ii) ?
I attached the question and mark scheme
paper code: 9701/42/F/M/18View attachment 64606 View attachment 64607
Conditions for adding a bromine across the double bond are not being fulfilled .Hey guys, please help me? The question asks for the reaction of serotonin with Br2 but the mark scheme says that only phenol reacts with it. Doesn't alkene c=c react too? I need an explanation for this. I'm so scared for coming exam
View attachment 64611View attachment 64612View attachment 64613
View attachment 64621 Need help with (ii)
How did you ended up with 10.8?Atomic mass is the weighted average of isotopic masses:
10.8 = 19.78%(10.0129) + 80.22%(m)
m = 10.9941 (6sf)
Atomic weight from periodic table.How did you ended up with 10.8?
Please explain iiView attachment 64625
There are some qs where its of 6 marks the best thing you could for it is Practice, Practice actually helps alot.Having problem/confusion in deducing molecule thorugh NMR pattern.
Taking alot alot of time and it is of only 1-2 or maximum 3 marks.
what should i do not getting better in it?How you people doing?
The rate equation depends on the slow step in the mechanism. Here step one is the slow and it needs no Y atoms and two X atoms.Also for this one , why is N zero order, why not first? Thanks a lot in advance
For step 4: why is the reagent aqueous Hcl and heat? We are turning amide to amine so shouldn’t it be reduction with LiAlH4?
https://www.facebook.com/463818014075291/posts/671605593296531/?sfnsn=modoes anyone have the 2019 march paper4?
But the amine will react with the acid and form ammonium ion in acidic hydrolysisThere is two ways to turn an amide to an amine
1) Hydrolysis, using HCL(aq) and heat
This breaks the amide linkage completely and you end up with two molecules, the amine and the acid
2) Reduction, using LiAlH4
Here you end up with one molecule, an amine, the carbons in the carboxylic acid group remain attached while the oxygen is removed
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