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hi. so3 + 2naoh ->na2so4 + h2o
mol of NaOH = 2.5 x 10^-3 mol = 2 x mol of SO2
mol of SO2 = 1.25 x 10-3 mol
Mr of X oxide = mass / mol = 0.1 / 1.25x10^-3 = 80 g/mol
SO3 is (3 x 16) + 32 = 80 g/mol
i did this backwards, knowing the answer as you've told. u can do it forwards by writing down each balanced equations and see which one fits.
mol of NaOH = 2.5 x 10^-3 mol = 2 x mol of SO2
mol of SO2 = 1.25 x 10-3 mol
Mr of X oxide = mass / mol = 0.1 / 1.25x10^-3 = 80 g/mol
SO3 is (3 x 16) + 32 = 80 g/mol
i did this backwards, knowing the answer as you've told. u can do it forwards by writing down each balanced equations and see which one fits.
