Chemistry: Post your doubts here!

[Snow Angel]

Snow Angel
View attachment 40897
Question number 4 b
As a secondary cation is more stable, the first reaction more often takes place.

thank u very much

 

[Snow Angel]

Basically because it has a week metallic bond. The mercury atoms doesn´t donate as much of their valence electrons to the cloud of electrons, so the electrostatic forces between the mercury cation and the delocalised sea of electrons isn´t as a strong metallic bond as say in magnesium, where there are more delocalised electrons and therefore more electrostatic forces of attraction.

oh thnx

 

[Snow Angel]

It's actually because there are relatively weaker electrostatic forces between its positive ions and its sea of electro s by Snowy Angel!!

ok thank u

 

[periyasamy]

You just saved my life!!!! *happy tears*

Haha.We always help each other,dont we...

 

[thats_me]

PLZ EXPLAIN IN DETAILView attachment 40903 View attachment 40904

 

[kitkat <3 :P]

How can we draw the reaction pathway for a reversible reaction :/

 

[robinhoodmustafa]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w09_qp_22.pdf

Q2 B)i)
This is regarding Diagram.. could anyone plz draw it out For Mee!
Thnx in Advance !

Each Na Connected to six Cl.Copied this from Endorsed Cambridge book.

*edit. Here is the image

 

[robinhoodmustafa]

How can we draw the reaction pathway for a reversible reaction :/

The product will become the reactant and Reactant be product..If exo than Ea will be high for reversible and if endo than Ea be low

 

[kitkat <3 :P]

The product will become the reactant and Reactant be product..If exo than Ea will be high for reversible and if endo than Ea be low

Thanks ^___^

 

[robinhoodmustafa]

Thanks ^___^

Think how a reversible reaction look like for endo and exo and just make the Opp of it

 

[abruzzi]

At cathode always reduction takes place
At the anode always oxidation takes place
So the object to be plated is at the cathode & it will gain the electrons from copper
You can remember it this way if it helps:
CCR- Cathode cation reduction & RIG- reduction is gain
AAO- Anode anion oxidation & OIL- oxidation is loss

Thanks a lot, I got it now
If you don't mind, could you please help me with qn no. 3(c) of this paper? It's a similar one.. and I'm completely confused
http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_s11_qp_42.pdf

 

[Faaiz Haque]

Simple.
Since it is an Alcohol,
When you add an oxidising agent such as K2Cr2O7 In Primary Alcohol ( OH on the end of the carbon Chain) Attached so you get an Carboxylic acid Or If its an Secondary Alcohol( OH wala Carbon attached to other two Carbon) so you get a ketone .


Presence of an Acid and Alcohol gives you an Ester. Memorize the structure of a ester. Add the Carboxylic chain on Front and Alcohol chain on the end.

When in presence of Hydrogen Hallide.. OH on gerian-ol ,The OH will be replaces by Br


Dont think how hard the name is . They make you feel like that but Just think which Functional group it contains and if this particular functional reacts with this reagent what will be formed. List down all the reaction and reagents on a page this will help u alot and will be easy to memorized .

Thanks a lot

 

[Faaiz Haque]

http://papers.xtremepapers.com/CIE/...d AS Level/Chemistry (9701)/9701_w05_qp_2.pdf

Question 5 f) With explanations

 

[chocolate_girl]

Somebody please draw 2px 2py 2pz orbitals nd also how to show orbital s s overlap nd sp overlap
Suchal Riaz

 

[Logitech]

http://papers.xtremepapers.com/CIE/... AS Level/Chemistry (9701)/9701_w07_qp_32.pdf
In this paper in Q1b how should I know which experiment to follow?

 

[AbbbbY]

View attachment 40878
Serious question people!! Please help. May Allah bless you all.

Been asked here the 8th time in 3 weeks and counting!

This stuff isn't in the syllabus or taught. This is precisely why it has shown you the 4 figures above the actual question. The examiner wants you to analyze those figures, see whats going on, and apply THAT to the question.

The question shows that all carbons in Benzene can be made to lie on the same plane, but not in cyclohexane. The question also shows that butane Carbons can be made to lie on the same plane, but methylpropane, also an alkane, cannot.
This tells us that if a compound has a ring, OR branching, it cannot be made to lie on the same plane.

All of them are co-planer apart from B.

C is coplaner because you don't have to consider the Oxygen atoms. The others are unbranched and two individual chains lying on the same plane.

Nice copy-pasta. I wonder why the writing style sounds eerily familiar. Oh rightt.. -.-

ON09 42 Q5a.
I've answered this before a day or two ago but I'll do it again anyway.
Look. This stuff isn't in the syllabus or taught. This is precisely why it has shown you the 4 figures above the actual question.... lying on the same plane.

 

[Logitech]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w05_qp_2.pdf

Question 5 f) With explanations

For the reaction of tollens reagent with an aldehyde the aldehyde gets converted into a carboxylic group. For the second one what you do is you remove the H2 from the 2,4 dinitrophenylhydrazine and from the other compound remove the O that is doubly bonded to the C. And then join both molecules together. The writing after the arrow is what should be written in the answer, the diagram before the arrow is for explanation.

 

[Mohammed salik]

Each Na Connected to six Cl.Copied this from Endorsed Cambridge book.

*edit. Here is the image

Thanx Dude! is this revision giude?

 

[AbbbbY]

Somebody please draw 2px 2py 2pz orbitals nd also how to show orbital s s overlap nd sp overlap
Suchal Riaz

Sorry for the crappy drawings. In my defence, drawing has never been my strength

 

[AbbbbY]

For the reaction of tollens reagent with an aldehyde the aldehyde gets converted into a carboxylic group. For the second one what you do is you remove the H2 from the 2,4 dinitrophenylhydrazine and from the other compound remove the O that is doubly bonded to the C. And then join both molecules together. The writing after the arrow is what should be written in the answer, the diagram before the arrow is for explanation.
View attachment 40925

Umm the stuff behind the arrow is also acceptable, and in fact it is recommended that it be used because it shows the placement of the Nitro groups (i.e 2,4)