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every year its difficulthi....can anybody tell me which year was the chemistry (or any other subject from phy,bio, fle,maths,ict, business studies) paper the most difficult???
P.S its urgent
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every year its difficulthi....can anybody tell me which year was the chemistry (or any other subject from phy,bio, fle,maths,ict, business studies) paper the most difficult???
P.S its urgent
isnt any year paper very difficult for majority???every year its difficultdepends on students capability
just see last 5 years oct/nov .... oct.nov are quite difficultisnt any year paper very difficult???
thnx a lot....just see last 5 years oct/nov .... oct.nov are quite difficult
see there isn't any year where all variants or components are difficult .....![]()
no problem and i hope that u got methnx a lot....
yup...definitely did![]()
Hi guys. Can you help me on a few past year questions? (ON 2013 P13)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w13_qp_13.pdf
Hope you could provide me steps/explanations to these questions(Whichever you could help with)ASAP. Thanks!![]()
Thanksull get CO2. u can also have it in a carbonate compound. depending on the reagent added like KOH or NaOH (any basic). since here NaOH was used so it can be NaCO3
Ans: NaCO3 /CO2
since there is an amine group due to hydrolysis(breaking bonds) it'll break apart n be in ion state or can be in amine compound which r stable enough.
so it may be CH3NH3+ Cl- or CH3NH2 (amine)
moreover, theres the aryl group there. so due to hydrolysis...the R group is seperated leaving the aryl group. i wont call it phenol exactly coz theres 2 rings joined there. so generalising it ...it becomes an aryl
in short answer : CH3NH3+Cl- and CO2 and the aryl with a phenol nxt to it (means one ring will have OH group on carbon 1)
welcomeThanksappreciated
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Sure why not..... can you please be specific. For which chapter are you talking about.Anyone can teach me how to use the chemical shift given in the official data booklet ?
It is confusing , it is so much different from the one given in the text book .
Sure why not..... can you please be specific. For which chapter are you talking about.
We have to find concentration of Nitrogen in that solidhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s08_qp_1.pdf
Can someone please explain me Question 2???????????
How did u convert grams to moles?We have to find concentration of Nitrogen in that solid
Answer ---> First of all we need to know how we can fine concentration
Conc = moles/volume
Units : Mol/dm3
Moles --> moles
Volume --> dm3
According to the ratio given of that solid material we have 15 gram of N per 100 g of fertiliser which means 15% and the usage of fertiliser in 14 g so :
14(15/100) ===> 2.1 grams.
Converting Grams to Moles we get ---> 0.15 moles
We have volume 5 dm3
Now put the values in equation :
Conc : 0.15/ 5 --> 0.03 mol/dm3
I hope you got it![]()
conc in g per dm^3 = conc in mol * MrHow did u convert grams to moles?
conc in g per dm^3 = conc in mol * Mr
so conc in mol= conc in g per dm^3 / Mr
Thank you!We have to find concentration of Nitrogen in that solid
Answer ---> First of all we need to know how we can fine concentration
Conc = moles/volume
Units : Mol/dm3
Moles --> moles
Volume --> dm3
According to the ratio given of that solid material we have 15 gram of N per 100 g of fertiliser which means 15% and the usage of fertiliser in 14 g so :
14(15/100) ===> 2.1 grams.
Converting Grams to Moles we get ---> 0.15 moles
We have volume 5 dm3
Now put the values in equation :
Conc : 0.15/ 5 --> 0.03 mol/dm3
I hope you got it![]()
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