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Chemistry: Post your doubts here!

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Why is the answer to this B and not A?
Reaction 1 is decomposition and decomposition reactions are always endothermic. That heating upto 1000 degrees Celcius was an absolute hint too.
Reaction 2 involves braking of a lattice and formation of Ca-OH bonds. If you use a data booklet, you will see that enthalpy of -OH ion is less than the enthalpy of -O.
 
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what does that imply?
Reaction 1 is decomposition and decomposition reactions are always endothermic. That heating upto 1000 degrees Celcius was an absolute hint too.
Reaction 2 involves braking of a lattice and formation of Ca-OH bonds. 'If you use a data booklet, you will see that enthalpy of -OH ion is less than the enthalpy of -O'.
 
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Can anyone please advise on how to solve calculations in titration questions in chemistry practical, im very bad at it , dont understand a simgle question :/
 
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For which reactions will writing "reflux" not be appropriate? Are there marks for writing it as a condition for other organic reactions??
 
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Re: All Chemistry help here!! Stuck somewhere? Ask here!

explain trend of solubility of group 2 sulphates.....well in anser to this.....we have to write that hydration enthalpy decrese faster than lattice bt i dont undrstnd how
The equation for the enthalpy of solution is. E= hydration energy - lattice energy so if the value of hydration energy is greater than the lattice energy then the enthalpy of solution will be positive. As a general rule, the more positive the enthalpy of solution is, the higher is the solubility. The hydration energy depends on the cations, so the difference in their size is relevant to the change in energy, while for lattice energy, neutral molecules are formed and since the sizes of the cations are negligible compared to the sulfate ion, the size of the molecule remains roughly the same as we decend the group so the lattice energy doesn't change that much, but as the the size of the cation increases down the group l, the hydration energy decreases significantly. Since the decrease in hydration energy is greater than the decrease in LE, the enthalpy of soliton is less positive and the solubility deceases
 
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If we remove three electrons from 3 half-filled orbitals from the same p subshell, why is there a small increase in ionization energy in each of them?
 
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Like, why is there an increase in 3rd to 4th I.E. and 4th to 5th I.E?
 
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