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Chemistry: Post your doubts here!

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2013 O/N Paper 13 Q. 3,14,17,22,28,39. Anybody please?
3)You use 10×0.30 = 3 moles of Tl^+ for every 20×0.10 = 2 moles of VO3^-. Every Tl^+ ion loses 2 electrons, so for every equivalent of Tl^+, you get 2(3) = 6 electrons to be taken up by the V atoms.

In VO3^-, V is present as +5. 6 electrons are taken up by 2 equivalents, so 1 equivalent will take up 3 electrons. This leaves you with +5 - 3 = +2.
 
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When asked to write about how temperature affects rate, do we mention the Boltzmann theory?
Can we just not write that kinetic energy increases so collision frequency increases?
please mention all d details dis answer should state..
 
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When asked to write about how temperature affects rate, do we mention the Boltzmann theory?
Can we just not write that kinetic energy increases so collision frequency increases?
please mention all d details dis answer should state..
You can write --> As temperature is increased more particles will have energy to react which leads to increases in successful collision between particles resulting in increase in rate of reaction.
 
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I want to ask about practicals in practicals then how much time do we actually need to prepare for biology and science practicals as I have practiced practicals for two months only 8 classes. So I am worried as i want to give as exam. My theory and mcqs skills are good. But I have been told that the student who gets B grade in practical gets an overall B in as exam. Is that true?
 
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I want to ask about practicals in practicals then how much time do we actually need to prepare for biology and science practicals as I have practiced practicals for two months only 8 classes. So I am worried as i want to give as exam. My theory and mcqs skills are good. But I have been told that the student who gets B grade in practical gets an overall B in as exam. Is that true?
well dont know about bio as well as anything about that grade thingy but i think 8 practicals r less u shld ask for more practise we hv done so far only titration and salt analysis and hv dun it like more than 6 times so we are rele gud at it but if u think u cn give it a shot at pracs and can score gud then it wld be fi9.
 
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Ans is B.
Enthalpy change=(Energy given out when bonds are made) - (Energy taken in when bonds are broken)
1800=2X-(994=496)
X=835KJ
SOrry i didnt get this part
How is it 1800?? shudnt it be 180?
n How is 994=496?? its a typing mistake i guess?
can u xplain it again?
1800=2X-(994=496)
X=835KJ
 
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snip...chem.PNG
so is it correct if i do the sum lyk this

n=(120*10^-3)/24
=5*10^-3

(5*10^-3)=0.23/mr
mr=46

(14*1)+(16*2)=46

am i ryt or is there a diff way 2 get it done?
 
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SOrry i didnt get this part
How is it 1800?? shudnt it be 180?
n How is 994=496?? its a typing mistake i guess?
can u xplain it again?
1800=2X-(994=496)
X=835KJ
Sorry it goes:
(N2 +O2)+2(NO)=180
(994+496)-180=2(NO)
=-655KJ
This is energy released when NO bonds formed but in question examiner only asks the energy of NO bond which is given in positive value ie he asks how much u will need for NO bond to break.
Hope u will understand.
 
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During the electrolysis of molten aluminium oxide to produce aluminium, using carbon electrodes,
two consecutive reactions occur at the anode, each producing a different gas.
How does the oxidation number of oxygen change in these reactions?

A decreases by 2, then increases by 2
B increases by 2, then decreases by 2
C increases by 2, then decreases by 4
D no change, then decreases by 2
 
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