- Messages
- 7
- Reaction score
- 1
- Points
- 13
Hi. Why is 2 a correct statement? Catalyst doesn't affect the yield of product isn't it? Answer is 1 and 2 are correct.
http://postimg.org/image/5sln0vven/
http://postimg.org/image/5sln0vven/
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
How would it possess cis trans if it was B?Why would it have 3 bonds? It has 4. (2 with one carbon, 1 with the top ethyl group, 1 with the bottom one) Besides, if it was B, then it would still possess cis-trans isomers.
Help please........ the ans is B
Which of these equations represents the reaction of sulphur dioxide with an excess of aqueous
sodium hydroxide?
A SO2 + NaOH ----> NaHSO3
B SO2 + 2NaOH -------> Na2SO3 + H2O
C SO2 + 2NaOH ------> Na2SO4 + H2O
D SO2 + 2NaOH -----> Na2SO4 + H2
Why cant it be reaction C???
It's complicated. http://www.chemguide.co.uk/basicorg/isomerism/ez.html#topHow would it possess cis trans if it was B?
The catalyst in experiment 1 could be faster (reduces activation energy more) than the one in 2. It has to do with speed, not yield. It would still stop at the same place as experiment 1, just taking more time.Hi. Why is 2 a correct statement? Catalyst doesn't affect the yield of product isn't it? Answer is 1 and 2 are correct.
http://postimg.org/image/5sln0vven/
Got it. ThanksThe catalyst in experiment 1 could be faster (reduces activation energy more) than the one in 2. It has to do with speed, not yield. It would still stop at the same place as experiment 1, just taking more time.
apart from balancing, is there any other concept behind the answer B?C isn't balanced. 4 O in reactants, 5 in products.
View attachment 54575
Why and how D?
If it's D then the Carbon before the R will only have 3 bonds :O
Why not B?
Why is option 2 correct?? I know it is true, but how is it even related to the theory? please help
Imagine a reaction which requires heat input of 10,000 kJ, to break the bond of the reactants. Then, as energy is produced when the bonds of the products are formed, let's say 9998kJ was formed. What's the overall enthalpy? +2kJ. It might seem at first that the reaction is easy to perform, but in fact, the activation energy is very high.Help please ........
The conversion of graphite has only a small positive value of H.
C (graphite) ---------> C (diamond) H = +2.1 kJ mol –1
However, the production of synthetic diamonds using this reaction is very difficult.
Which statements help to explain this?
1 The activation energy of the reaction is large.
2 An equilibrium exists between diamond and graphite.
3 Only exothermic reactions can be made to occur readily.
The Ans is D
For this question, the correct answer is B. However, I got the answer A...
My working steps are:
K2O+H2O->2KOH
2KOH+H2SO4->K2SO4+2H2O
Found the no of moles for H2SO4, which is 0.03 mol, then used mole ratio and got the no of moles for KOH, which is 0.06 mol
I then used mole ratio and found no of moles for K2O, 0.03 moles
Mass of K2O=o.o3 mol X Mr K2O
=2.83 .....
http://postimg.org/image/vd4jealez/
Option 2 is incorrect. Sulfuric acid can act as an acid because the oxygen atom in ethanol has two lone pairs, either of which can accept the proton.
Oh yeah I thought It said it does behave as an acid..
Though even if it said that & the statement was that H2So4 behaves as an acid in ethanol.. wud that be correct here? Is it related to the theory? :s If yes, is it because, as you mentioned, oxygen in ethanol accepting the proton??
Great explanation, thank you sooo muchImagine a reaction which requires heat input of 10,000 kJ, to break the bond of the reactants. Then, as energy is produced when the bonds of the products are formed, let's say 9998kJ was formed. What's the overall enthalpy? +2kJ. It might seem at first that the reaction is easy to perform, but in fact, the activation energy is very high.
Therefore, statement 1 is correct.
Statement 2 is obviously wrong. (Btw this allows you to choose D immediately)
Statement 3 is not true. Some endothermic reactions can be rapid as well. Dissolving sugar is not that hard is it? It's endothermic.
Oh i thought for cis-trans you have to have 2 same components on the 2 carbon chainsIt's complicated. http://www.chemguide.co.uk/basicorg/isomerism/ez.html#top
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now