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No it's A
How are the bonds supposed to break in this compound?
Theoretically, as long as the products have same or lesser carbons than the original molecule, they can be formed upon cracking
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No it's A
How are the bonds supposed to break in this compound?
Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed
Actually in cracking reactions you can make any alkane or alkene (given that no of carbon atoms and hydrogen atoms are less or equal to the reactant (Alkane Or Alkene )
Btw I thaught only cracking of alkanes is possible.... anyidea if cracking of Alkynes or Arenes possible or not???
Plz help me with these
View attachment 63734 View attachment 63735 View attachment 63736[/QUOT
enthalpy change of Hydration is always exothermic. hence reaction 2 is exothermic
At 1200, the bond is C-ONeed Help with these :3View attachment 63745 View attachment 63744
For 9, the bonds being broken are 1 C=C and 1 H-Br and those forming are 1 C-C, 1 C-H and 1 C-BrNeed Help with these :3View attachment 63745 View attachment 63744
Thanks a bunchAt 1200, the bond is C-O
At 3400, it is O-H and since there is no other absorption mentioned, so it can not be a carboxylic acid, therefore, its just an alcohol
according to the formula, there are 4 isomers
Oh i get it now i just missed to add C-C single bondFor 9, the bonds being broken are 1 C=C and 1 H-Br and those forming are 1 C-C, 1 C-H and 1 C-Br
Enthalpy change = +610 +366 -350 -410 -280 = -64
J is sulfur which has 6 electrons in its outer shell...2s and 4p so 1p orbital has 2 electronsElement J is a solid. It occurs as a contaminant of fossil fuels. Its oxide K is formed in car engines. In the atmosphere, K can be further oxidised to L. Which statements about J, K and L are correct? 1 Atoms of J have paired p electrons. 2 The atmospheric oxidation of K to L is a catalysed reaction. 3 With water, L forms a strong acid.
the answer is A how is option 1 correct? help!
but two electrons the the p subshell are unpairedJ is sulfur which has 6 electrons in its outer shell...2s and 4p so 1p orbital has 2 electrons
But atleast it has SOME paired electrons, which makes the statement correctbut two electrons the the p subshell are unpaired
Its B and its not A as catalyst increases rate but does not effect equilibrium so it can be seen that the it is referring to equilibrium due to pressure still being high enough. Besides im pretty sure catalyst were used that time as well for this reaction unless they were invented recently xD.Why can't it be A?
oh makes sense. thanksBut atleast it has SOME paired electrons, which makes the statement correct
There can be no acid base reaction between bases and bases. Statement 2 is wrong as Sulfuric acid is an oxidising agent and can oxidise ethanol whilst being reduced in the process meaning it lost proton/H+ ionCan someone plz explain statement 2 and 3? How is 2 wrong?
That's the conversion from ethanol to ethene, right? And does the H+ from sulfuric acid react with OH- from alcohol?There can be no acid base reaction between bases and bases. Statement 2 is wrong as Sulfuric acid is an oxidising agent and can oxidise ethanol whilst being reduced in the process meaning it lost proton/H+ ion
No i was talking about the oxidation of alcohols to form Carboxylic acid and etc in which we oxidise by acidified KMnO4 and the acid used is usually sulfuric acid to acidify KMnO4.That's the conversion from ethanol to ethene, right? And does the H+ from sulfuric acid react with OH- from alcohol?
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