Further Mathematics: Post your doubts here!

[ahzahra]

alzahra, what's giving you a problem on it? It's a pretty simple one if you understand vector spaces. Or do you just want a solution? I can help with either.

I just need the answers, as I understand there could be more different basis vectors in V3 than those mentioned in the report. I need details on the answer. How come the dimension is 2?

 

[ahsanxr]

Sorry for taking so long to get back to you but hopefully I can still be helpful. Here's how to do June 02 Problem 10, feel free to ask other questions as well. Oh and ignore the line in the middle of the page.

 

[abcde]

Find the particular solution for the following differential equation for which y = 8 and dy/dx = -27 when x = 0.
My general solution is correct. However, the values of the constants I'm getting for the particular solution are different from what the book calls correct.
The correct answers are A = √375 and tan ε = - 17/6. Please verify this.

 

[OakMoon!]

With the given answers, you don't even get dy/dx equal to -27.

 

[abcde]

What answer do you get? The book solution seems wrong.

 

[abcde]

I guess I'm missing out on a simple concept here but what is the reason behind the step shown?

 

[OakMoon!]

Yes, you are missing on a simple concept. The angle pi/8 and 2pi-pi/8 have the same magnitude for sine and cos. Except that the sine here is negative as it lies in the 4th quadrant.

 

[abcde]

Do you mean angles 2pi/8 and (2pi - 2pi/8) have the same magnitude?

 

[OakMoon!]

Their Cosine and Sine values have the same magnitude.

 

[abcde]

Yes, I meant that.

 

[mrpaudel]

Guys..do we have the book for further maths endorsed by CIE??? not the edexcel one...!! i need the book itself..do we have the link for that one?

 

[abcde]

Find the angle between the following pair of lines:
(x - 2)/3 = (y + 1)/-2 , z = 2
(x - 1)/1 = (2y + 3)/3 = (z + 5)/2

 

[OakMoon!]

 

[abcde]

Or we could simply use the direction ratios of both equations, which are 3: -2 : 0 and 1: 3/2 : 2 and insert the required values into the dot product equation (shorter).
The above made me realise a silly error I made while writing the direction ratios of the second equation.
Thank you

 

[OakMoon!]

Direction ratios is the direction vector. I prefer working with the vector form that is why I converted them first. You can choose your way of solving the question.

 

[abcde]

I can see that. There was no point of the above post.

 

[OakMoon!]

Oh please, I didn't mind writing a post and replying to your remark of using another way to solve the question. Not lazy.

 

[abcde]

Point taken.

 

[liuweijian94]

guys~~~can any one help with s05 qp2 question 2, a mechanics question....thanks

 

[liuweijian94]

and the question 10 in s05 qp2, statistics problem...... i can not show that f(y^1/2) is equal to the answer....there are two function in 0<y<1 ...