Further Mathematics: Post your doubts here!

[talhajohar]

guys~~~can any one help with s05 qp2 question 2, a mechanics question....thanks

Here is the solution. Hope you get it.

 

[maltafgab]

Further maths question- can anybody help???
Solve Questoin 3 and 5 of this paper plz...!

http://www.xtremepapers.com/CIE/Interna ... 5_qp_2.pdf

 

[talhajohar]

Further maths question- can anybody help???
Solve Questoin 3 and 5 of this paper plz...!

http://www.xtremepapers.com/CIE/Interna ... 5_qp_2.pdf

 

[abcde]

AoA!
This is a simple question but I'm unable to get the required answer.
Simplify (using De Moivre's Theorum): (2 - √3 i)^6

 

[abcde]

Secondly, while evaluating 1/(sin x + i cos x)^6 , the answer I get is - cos 6x - i sin 6x. The correct one is: - cos 6x + i sin 6x.

 

[talhajohar]

AoA!
This is a simple question but I'm unable to get the required answer.
Simplify (using De Moivre's Theorum): (2 - √3 i)^6

whats the answer?

 

[abcde]

AoA!
This is a simple question but I'm unable to get the required answer.
Simplify (using De Moivre's Theorum): (2 - √3 i)^6

whats the answer?

512i.

 

[talhajohar]

the answer seems wrong. you can check it by solving it on calculator.

 

[OakMoon!]

The answer is -141+312i

 

[abcde]

The answer is -141+312i

Yes, I'm getting the same.

 

[OakMoon!]

That's the answer. If you want to confirm such qualitative answers, just visit wolframalpha.com.

 

[maltafgab]

Please solve these questions for me
Further maths P2> Nov-05, Q 5
Nov- 06, Q 1
Nov-07 , Q 11 either

 

[maltafgab]

Oh Thanks man
it was really a great help for me
i m really grateful to you
Hope to see u again

 

[OakMoon!]

^ Q5 Nov 05

 

[OakMoon!]

 

[fhdaly]

Question 4 May/june 2004 Mathematical induction. How do we solve the second part? A tricky one seriousli!

 

[OakMoon!]

Mind the poor quality. My scanners' scan screen got half burnt. Plus, I messed up the negative sign so the editing.

 

[fhdaly]

thanks, but what i need to understand is that how did we get a=(-1)^n n! in the first place? did we just assume it? how?

 

[OakMoon!]

thanks, but what i need to understand is that how did we get a=(-1)^n n! in the first place? did we just assume it? how?

We get it by observing the three values you have got. Since, the -ve sign is bein alternated, we know that the first value is (-1)^n. Further, observing the values show us that it has to have factorial. This is a general rule of forming a conjecture. It's just a proposition from your side.

 

[OakMoon!]

Here is an example of another type of conjecture: https://docs.google.com/viewer?a=v&...q9zBD9&sig=AHIEtbSwggUiYLyNBgXLTtI3Aq5J41Ct0Q