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How did the physics 22 paper go?

How much do you expect?

  • 50 - 60

    Votes: 24 27.0%
  • 40 - 50

    Votes: 34 38.2%
  • 30 - 40

    Votes: 29 32.6%
  • < 30

    Votes: 2 2.2%

  • Total voters
    89
  • Poll closed .
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Hahahhaha ur idea was epic (y) :LOL:

Hmm yes what i did was like this:(2*7.66)-22.7=-7.38m .-.
How did you get to that conclusion?I used distance travelled up-distance travelled down

7.66-15.0=-7.33

- so ans i opposite direction i.e downwards.
 
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How did you get to that conclusion?I used distance travelled up-distance travelled down

7.66-15.0=-7.33

- so ans i opposite direction i.e downwards.
What i did was: total distance- distance travelled up and down of EQUAL height to get the remaining height....
For example: if distance moved up and down were equal, both will cancel each other and give 0 but the extra distance travelled down will be found.

I calculated urs too... We did the same thing. The only difference is that i wrote 22.7 instead of its accurate value thats it.
 
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What i did was: total distance- distance travelled up and down of EQUAL height to get the remaining height....
For example: if distance moved up and down were equal, both will cancel each other and give 0 but the extra distance travelled down will be found
Im not quite getting it though,How does that give the extra distance?
 
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Total distance- upper part of the displacement time graph... The whole semi circle(if its a semi circle)... This will give us the negative portion of the graph
Its not a circle its a parabola,similar to ta graph of x^2
But total distance minus uppar part distance will give 22.7-7.66=15m
 
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Its not a circle its a parabola,similar to ta graph of x^2
But total distance minus uppar part distance will give 22.7-7.66=15m
-_________- w8 lemme show u an evidence:
I hope now u understand what I did :/ (plz say i did it correctly :/)
11082214_851973608209689_527130308079539101_o.jpg
 
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