How was Chemistry 42?

[FRENZYAMU]

idk if light blue ppt is important to list or not, but since it was aqeous an intermediate of Cu[h2o]2[nh3]4 would be formed....

also the split happens because of dz2 and dx2-y2 which are close to bonding pairs causing them to go to higher energy level, whereas these orbitals are not present in s-orbital compounds.

for drugs the monomer was i think di-carboxyl group acid and the joining/cross-link forming compound was di-hydroxyl compound.

for NMR questions idk the compound but Cl was element, and 7 carbon atoms.

nd protons 7 too right ?

 

[leosco1995]

It was C7H7ClO.. meaning a benzene ring.

 

[FRENZYAMU]

what happened when u increased the Cr+2 concentration.... ?,,,,nd they said that SO2 reacted in presence of H+ with KMNO4 but when i made the equation, the H+ came out to be on the RHS nd not the LHS side of eq

 

[Jinkglex]

No observation because cr2+-> cr + 2e- was not feasible reaction

 

[ganapathynar]

dude the E knot value was positive of course it was feasible. It changes to green

No observation because cr2+-> cr + 2e- was not feasible reaction

 

[Jinkglex]

dude the E knot value was positive of course it was feasible. It changes to green

I dont think so....since Cr2+ + 2e -> Cr is -0.91 or something....meaning you cannot reduce Cr2+ with K2Cr2O7...

 

[ganapathynar]

I dont think so....since Cr2+ + 2e -> Cr is -0.91 or something....meaning you cannot reduce Cr2+ with K2Cr2O7...

what about cr2+ to cr3+ and k2cr2o7 to cr3+ that reaction is possible

 

[ganapathynar]

i dont think it said specifically that Cr2+ should get reduced. i think it just said reaction with Cr2O7- ions

I dont think so....since Cr2+ + 2e -> Cr is -0.91 or something....meaning you cannot reduce Cr2+ with K2Cr2O7...

 

[ganapathynar]

I dont think so....since Cr2+ + 2e -> Cr is -0.91 or something....meaning you cannot reduce Cr2+ with K2Cr2O7...

Do you remember the question? i just remember some parts being Cr2+ being blue in colour and then calculate E knot value for reation with Cr2O7-

 

[Jinkglex]

the question was just what would happen if we added k2cr2o7 to cr2+ in solution. And yes actually cr3+ would be formed, i didnt see that equation :/

 

[ganapathynar]

the question was just what would happen if we added k2cr2o7 to cr2+ in solution. And yes actually cr3+ would be formed, i didnt see that equation :/

oh shit that is something you should have checked out! :/ . If we used both those equations that i posted, wouldnt the e knot value be just 0.91? assuming the k2cr2o7 equation is 1.33 and the other is -0.41?

 

[Jinkglex]

No E value would become 1.33+0.41 = 1.74. Color would turn green im guessing.

 

[Jinkglex]

And yeah :/ Oh well, 13 marks lost up till now i guess!

 

[ganapathynar]

sorry 0.92

the question was just what would happen if we added k2cr2o7 to cr2+ in solution. And yes actually cr3+ would be formed, i didnt see that equation :/

 

[ganapathynar]

And yeah :/ Oh well, 13 marks lost up till now i guess!

dont worry same boat as you

 

[Jinkglex]

dont worry same boat as you

oh well...im expecting the GT to be pretty low

 

[ganapathynar]

oh well...im expecting the GT to be pretty low

one more question, if the gt was as low as 55 wouldnt everybody get A's ? Its something really hard to imagine! :O

 

[Jinkglex]

Not really, there are ALOT of people out there who dont even study, or who just dont get the question etc and bring the GT low

 

[ganapathynar]

Not really, there are ALOT of people out there who dont even study, or who just dont get the question etc and bring the GT low

you are making me feel a lot better!!!

 

[Mano77har]

What were the order of the reactions in the first question? I got zero for NaOH..and if thats wrong will I lose all the marks of the questions below dat? :/