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it was no because the value shown on protractor is 59 and avg was 20
so how is it possible?
so how is it possible?
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it was no because the value shown on protractor is 59 and avg was 20
so how is it possible?
Ah, I gave 61, it was really easy Alhumdulilah!![]()
the value shown wasn't 59 :|it was no because the value shown on protractor is 59 and avg was 20
so how is it possible?
no it is nothe said the average and value of alpha =/=
the value of alpha is the diagonal u drew at the recangular
it is not whatever I like it was another experiment where he kept the protractor and measured the angle but 19 was the question before itwhatever you like bro![]()
it is not whatever I like it was another experiment where he kept the protractor and measured the angle but 19 was the question before it
answer for question 2 ?
Question 2, last part; I got o.1 cm. I discussed it with my friends and they all got the same answer.
no thats wrong u included the length of the bulbMine Was 0.16
When Temperature Was 80C Distance Was 11.9
If It Is 1C
Then We Will Do Cross Multiply
(11.9*1)/80
You Will Get An Answer Between 0.15~0.17
Just Do The Same Procedure Several Times (Around 3) With Different Readings From The Table
And Get The Mean
And It Was 0.16
I Aint Sure Btw
But Howcome Its 0.1??
Even If You Tried To Measure It By The Ruler
Its More Than 1mm/0.1cm
!!!!!
anything reasonable answer would be correct, the load my slip, the rule may slip, difficult to place the load exactly on the cm mark ....etcpaper 6 was OKAY not easy
what was the answer for last page,the practical diffuclty and how to overcome it? and the number of measurements too?the gradient?
howcome its 0.1
i got 0.16
by doin cross multiply
tell me da calculation
I got 0.15... cuz 80 ----> 11.9 cm
1 -----> x
therefore x= (1 x 11.9)/ 80
x = 0.15
the answer should be by cross multiplication, I think
0.15 0.16 ARE OF THE SAME RANGE
the problem is dat students wrote 0.1
i dont knw which one is correct![]()
I'll tell u the correct answer, you are going to measure the distance of 10 dgrees celsius, then divide the answer by 10 to get the distance between each 1 degree celsiusI know.. I was telling you that I did the same calculations...
I really hope its the correct answer :/
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