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[Awesome12]

Omar is in which team?

People you don't know

 

[MarcoReus]

Lel. Seems like I missed the train then. Every team is full now.

 

[M.Omar]

Omar is in which team?

Da Hell is with u and FLRNAB liking every post . And yeah thnx for tht by the way

 

[exploded diper]

Are my answers correct

 

[exploded diper]

During landing an aircraft a speed changes to zero. Explain how momentum is conserved in the complete landing process?

 

[exploded diper]

 

[F.Z.M. 7]

During landing an aircraft a speed changes to zero. Explain how momentum is conserved in the complete landing process?

There isnt anything colliding?

 

[exploded diper]

There isnt anything colliding?

The aircraft and the land

 

[F.Z.M. 7]

The aircraft and the land

Earth is gonna rotate slightly faster then

 

[exploded diper]

Earth is gonna rotate slightly faster then

So can I say Tht the momentum is transferred into te earth hence the total initial momentum is equal to total final momentum

 

[exploded diper]

use the defination of acceleration to explain why the velocity of a body may be i different direction from its acceleration?

 

[asadalam]

Guys wheres the MF9 page file for math formulae?i cant find it..

 

[exploded diper]

Someone answer my questions
M.Omar

 

[M.Omar]

View attachment 48563 View attachment 48561

Well u do know tht option C and D r out of the way as the value of a wud decrease over time.I think this question refers to the happenings on the latch at an instant.For example we know tht at the release pt,where spring is most compressed,instantaneous force is most and as the spring stretches,the instantaneous force exerted at any following instants wud be less than the instantaneous force exerted at a previous instant.Hence,due to instantaneous force decreasing with increase in x,the instantaneous acceleration wud also decrease and this shows up in the 2 graphs(A and B).Now abt the proportionate and non proportionate part:U do know tht if force is increased by constant factor(i.e weight on suspended spring is doubled(or any other factor like tripled,quadrupled,halved)) on a suspended spring it will stretch/increase in length with same factor(wight is doubled then so is the length) hence we can consider the fact tht when it,it released from its compression state,it will exert a force which will be instantaneously decreasing(tht i have explained before) but also tht the force exerted will decrease at a proportionate rate in consideration of the proportionate decrease in length.Since force decrease at a constant rate,the value of a also decreases at a constant rate...

 

[M.Omar]

use the defination of acceleration to explain why the velocity of a body may be i different direction from its acceleration?

Acceleration is change in velocity per unit time..
Case 1 :If velocity is decreasing then acceleration is at opposite side of the velocity..Case 2:When turning a corner(circulr arc) at constant speed .Instantaneous velocity is tangent to circular arc and acceleration is towards the center e.t.c

 

[M.Omar]

View attachment 48563 View attachment 48561

u sure it,s D?

 

[exploded diper]

u sure it,s D?

no i just had a hunch ....

 

[exploded diper]

Well u do know tht option C and D r out of the way as the value of a wud decrease over time.I think this question refers to the happenings on the latch at an instant.For example we know tht at the release pt,where spring is most compressed,instantaneous force is most and as the spring stretches,the instantaneous force exerted at any following instants wud be less than the instantaneous force exerted at a previous instant.Hence,due to instantaneous force decreasing with increase in x,the instantaneous acceleration wud also decrease and this shows up in the 2 graphs(A and B).Now abt the proportionate and non proportionate part:U do know tht if force is increased by constant factor(i.e weight on suspended spring is doubled(or any other factor like tripled,quadrupled,halved)) on a suspended spring it will stretch/increase in length with same factor(wight is doubled then so is the length) hence we can consider the fact tht when it,it released from its compression state,it will exert a force which will be instantaneously decreasing(tht i have explained before) but also tht the force exerted will decrease at a proportionate rate in consideration of the proportionate decrease in length.Since force decrease at a constant rate,the value of a also decreases at a constant rate...

so tht means the answer is a right?

 

[M.Omar]

so tht means the answer is a right?

i think tht wud be so

 

[M.Omar]

no i just had a hunch ....

I think it,s B as 100 -20 =80 N downwards on right hand side..So to pull at 50 rev/s in opposite dir which means at 15m/s(circumference times rev) wud give power as Force *velocity i.e 80*15 =1.2kW