Math 32....how was it? :/

[sweetyrox]

Seriously , This was one of the most difficult paper in history of P-3
Not only lengthy but tricky too
don't expect too high marks believe me

53 -55 - for A grade
43 -45 - for B grade

I really hope that the thresholds are lowww ..

Believe me most of the candidates found it difficult percentile is certainly LOW
Nov 2011 was way tooooo easier than this and percentile was like 58

 

[Gooners]

yeah i got the same!

I got pi/2(e^2-1) :/

 

[earthling]

I got pi/2(e^2-1) :/

Let's all have a moment of silence for the marks you've lost......

 

[earthling]

how much marks were for the volume of rev part ?

SEVEN!!!!

 

[MindStealth]

Do you hav ny idea of how many marks will be deducted?

Not more than 2...probably just 1 mark.

 

[earthling]

n wat abt vector last part

i messed in 6mark part of integarting I, 7 mark volume of rev. last part of vector

I lost marks there too... That was 6 marks(last part of vector question)

 

[solidboy123]

Yaar anyone remembers the equation for finding the volume which was given in the question

 

[aliya_zad]

Yr in the volume of revo!
We had to do y^2 so
If wrote xlnx^2 instead of x(lnx)^2
Will i be loosing all of 7 marks cuz i did the whole working pretty good and
Got the answer of (pi)(e^2 /2 - 1/2)
so hw much marks will b loosing?? Ny idea??? :/

I did it (ln x)^2 and got the same answer as u did!!
So may be it doesnt make such a big difference coz u have integrated in the same way..and Got the Right answer..

 

[aliya_zad]

Yaar anyone remembers the equation for finding the volume which was given in the question

Yeah its pi ( y )^2 and to find the volume u integrate it!

 

[aliya_zad]

Cosec2x=secx+cotx plz

(1/sin2x) = (1/cos x) + (cos x/sinx)
(1/2sinxcosx) = (1/cos x) + (cos x/sinx)
multiply each by cos x
(1/2sinx)= 1 + (cos^2 x/sinx)
Multiply each by sin x
1/2 = sin x + Cos^2 x
write cos^2 x in terms of sin x
1/2 = sin x + (1-sin^2x)

It comes down to
Sin^2 X- sin x-1/2=0
2Sin^2 X- 2sin x-1=0

 

[leadingguy]

i found da paper not difficult but lengthy didn't get time to rechk my work!

how much expecting??

somebody post answeeeeeeeeeeerrrs!

no not al plz leave it no answers

i found it ok..................
though it was hard but i managed...........

so how good U managed??? what are u expecting??

 

[Gooners]

(1/sin2x) = (1/cos x) + (cos x/sinx)
(1/2sinxcosx) = (1/cos x) + (cos x/sinx)
multiply each by cos x
(1/2sinx)= 1 + (cos^2 x/sinx)
Multiply each by sin x
1/2 = sin x + Cos^2
1/2 = sin x + (1-sin^2x)
It comes down to
Sin^2 X- sin x-1/2=02Sin^2 X- 2sin x-1=0

I did by exactly the same method and probably came down to sucha an equation!!
But my friends say tht as it is nt proven as an Identity so u cannot multiply (cos X) on both sides to cut it!!!
Any idea about it!??

And gyz wat was the answer to volume of revo Q?
I got pi((e^2)/2 -(1/2)) !!!!
And my friends who integrated lnx whole squared are getting the same answers!! :/

 

[Gooners]

Let's all have a moment of silence for the marks you've lost......

What happns, just happns!!
So what was ur answer fr volume part earthling!?

 

[angelicsuccubus]

(1/sin2x) = (1/cos x) + (cos x/sinx)
(1/2sinxcosx) = (1/cos x) + (cos x/sinx)
multiply each by cos x
(1/2sinx)= 1 + (cos^2 x/sinx)
Multiply each by sin x
1/2 = sin x + Cos^2 x
write cos^2 x in terms of sin x
1/2 = sin x + (1-sin^2x)

It comes down to
Sin^2 X- sin x-1/2=0
2Sin^2 X- 2sin x-1=0

!"£$%^$&££%^&$^%NM I read that as tryna prove the identity.. I could have got those 6 marks like *snap of fingers* that! and I was like.. why the freak isnt this proving each other!! ='[ !!!

 

[aliya_zad]

I did by exactly the same method and probably came down to sucha an equation!!
But my friends say tht as it is nt proven as an Identity so u cannot multiply (cos X) on both sides to cut it!!!
Any idea about it!??

And gyz wat was the answer to volume of revo Q?
I got pi((e^2)/2 -(1/2)) !!!!
And my friends who integrated lnx whole squared are getting the same answers!! :/

They had asked as to find the solutions rite?? So yeah we can multiply cos x on both sides to cut it..

Yeah and integration i got the same answer Too..MashAllah!

 

[sparten]

I got pi/2(e^2-1) :/

yea i got the same answer

 

[sparten]

I did by exactly the same method and probably came down to sucha an equation!!
But my friends say tht as it is nt proven as an Identity so u cannot multiply (cos X) on both sides to cut it!!!
Any idea about it!??

And gyz wat was the answer to volume of revo Q?
I got pi((e^2)/2 -(1/2)) !!!!
And my friends who integrated lnx whole squared are getting the same answers!! :/

my volume was same as yours

 

[khanboy007]

(1/sin2x) = (1/cos x) + (cos x/sinx)
(1/2sinxcosx) = (1/cos x) + (cos x/sinx)
multiply each by cos x
(1/2sinx)= 1 + (cos^2 x/sinx)
Multiply each by sin x
1/2 = sin x + Cos^2 x
write cos^2 x in terms of sin x
1/2 = sin x + (1-sin^2x)

It comes down to
Sin^2 X- sin x-1/2=0
2Sin^2 X- 2sin x-1=0

Thank u

 

[earthling]

What happns, just happns!!
So what was ur answer fr volume part earthling!?

It was....FOR THE LAST TIME ...... Pi/4(e^2 - 1)

 

[princesskt]

It was....FOR THE LAST TIME ...... Pi/4(e^2 - 1)

i got the same.......................