Mathematics: Post your doubts here!

[Lost_Life]

Actually I Always Practice In IG Exams They're Full Of Questions

Do You Know The Rules For Simple And Compound Interests ?

i guess so... is it, for simple, P*R*T(in years)/100... and compound is p(1+r)^n

 

[Just Smie :)]

i guess so... is it, for simple, P*R*T(in years)/100... and compound is p(1+r)^n

Yup that's it. And Usually The question is about either simple or compound. Not Both

 

[Someone2]

how do we solve this?
find the integers of n
9<3n+6<= 21

u divide the inequality into two: 9<3n+6 and 3n+6<=21
For 9<3n+6 it will bcum 1<n
For 3n+6<=21 it will bcum n<=5
so 1<n<=5 n i think 4 this ques ur supposed 2 find the integers so the ans is 2,3,4 &5
hope u got it!

 

[Just Smie :)]

is the answer (( -12 )) ??

I Think It Is 1 or 5 ?

 

[Just Smie :)]

u divide the inequality into two: 9<3n+6 and 3n+6<=21
For 9<3n+6 it will bcum 1<n
For 3n+6<=21 it will bcum n<=5
so 1<n<=5 n i think 4 this ques ur supposed 2 find the integers so the ans is 2,3,4 &5
hope u got it!

Yes I Think That Is The Correct Answert Too !

 

[Lost_Life]

Yup that's it. And Usually The question is about either simple or compound. Not Both

well i get really REALLY confused in questions like that, i mean, i would have never thought to add..

 

[Just Smie :)]

well i get really REALLY confused in questions like that, i mean, i would have never thought to add..

The Question Comes Quite Obvious If Total Is Required Then The Question Would Be Like This One. If The Interest Only Is Required Then It Would Be Calculate How Much Interest Instead

 

[always-smile :)]

any predictions for the exam ??

 

[Just Smie :)]

any predictions for the exam ??

Think It's Gonna Be Okay,Not So Easy But Not So Difficult Also...

 

[Lost_Life]

Think It's Gonna Be Okay,Not So Easy But Not So Difficult Also...

Hope so..

 

[always-smile :)]

Hope so..

isA cuz really i'm freaking out

 

[Lost_Life]

how do we solve 9 c MJ 2011 PAPER 4 VARIANT 2

 

[сᴏᴏʟ сяуѕтᴀʟѕ]

u r always in ma prayers..

Jazakallah Khair..May Allah bless yoU

 

[Maz]

how do we solve 9 c MJ 2011 PAPER 4 VARIANT 2

You solve it using quadratic equations.
1st equation is : a + b +1 = 3
2nd is : 8a+4b +2 =12

 

[always-smile :)]

how do we solve 9 c MJ 2011 PAPER 4 VARIANT 2

first substitute n=1 ---> a+b+1=3 (( 3 the no. of lines in diagram 1 ))
then n=2 ---8a+4b+2= 12 ((( 9 lines of diagram 2 plus 3 lines from diagram 1 ))
then solve them together

 

[Hamzeh S]

Guys when is the shear and stretch negative factor ?? i mean i saw a question and one of the point was at (-1 1) and it moved 1 to the up i though the scale factor was shear scale factor 1 y axis invarient but turned out scale factor is -1 ? can you please explain

 

[Maz]

Umm... did anyone get the answer to the question which khushbukr asked?

 

[lol]

how is it possible to get a negative Shear factor? i sdont remember thequestion buti have seen some shears in pastpapers with factor -1 , etc
how/why is it negative? can someone explain

 

[always-smile :)]

Umm... did anyone get the answer to the question which khushbukr asked?

i want the same question 2

 

[always-smile :)]

Did you guys try solving it?? Even though it's just for one mark, not being able to solve it is frustrating!

i did try but i didn't get the right answer and that is a frequent question almost in all exams :s