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Mathematics: Post your doubts here!

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i)
Taking theta = x
a=x rads
a6= 4x rads

S6 = 6/2 (2(x) + 5d)
We know that S6 = 2pi
2pi = 6x + 15d ----1

a6 = a + 5d
4x = x + 5d
d=3x/5 ----2

Put 2 in 1 and you should get the value of x.

The perimeter of the smallest sector = rx + r + r





thank u for help :):) easy :oops::p;););)
 
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Does anyone know how to differentiate this? :unsure: Thanks
diff.jpg
 

Dug

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Does anyone know how to differentiate this? :unsure: Thanks
diff.jpg
To find derivatives of equations like this one, its best to break it up.
A= [(pi x^2 +4x^2) / pi] - (160x/pi) + (1600/pi)
Simplifying further,
A = [ x^2 + {(4x^2)/pi}] - 160x/pi + 1600/pi
dA/dx = 2x + 8x/pi -160/pi
 
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To find derivatives of equations like this one, its best to break it up.
A= [(pi x^2 +4x^2) / pi] - (160x/pi) + (1600/pi)
Simplifying further,
A = [ x^2 + {(4x^2)/pi}] - 160x/pi + 1600/pi
dA/dx = 2x + 8x/pi -160/pi
I gave the same answer:p But I didn't simplify it:D yours is long , just simply seperate 1/pi frn the equation and then find the derivative and put back 1/pi again:D
 
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To find derivatives of equations like this one, its best to break it up.
A= [(pi x^2 +4x^2) / pi] - (160x/pi) + (1600/pi)
Simplifying further,
A = [ x^2 + {(4x^2)/pi}] - 160x/pi + 1600/pi
dA/dx = 2x + 8x/pi -160/pi
How do we get it in this form though?
NewPicture3-1.jpg

Thanks
 
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kjnjknk.png


People please help i cant figure out how to solve the second part. the answer in marking scheme is 7pi/12 but some how i end up getting pi/12.. please help asap i have amy maths exam tomorrow. :'(
this question is from summer 09 qp1.
 

Dug

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I gave the same answer:p But I didn't simplify it:D yours is long , just simply seperate 1/pi frn the equation and then find the derivative and put back 1/pi again:D
I think the 'long' method reduces the chances of errors because everything is kinda 'opened'. Plus, I am sure you've heard the saying "Old habits die hard". :cool:
 
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