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please I hope u will solve question 9)iii) nov qp 33 2011 mathematics A2 9709
but please as soon as possible because my exam is on 16 May
thanks
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please I hope u will solve question 9)iii) nov qp 33 2011 mathematics A2 9709
but please as soon as possible because my exam is on 16 May
thanks
You sir,deserve a Trophy and a million likes.Whoaa that was a hectic task to write all that at MS Word :\
By the way here u go !!
Ahhh No problem !!You sir,deserve a Trophy and a million likes.
thanks a lot mate.
i)
Taking theta = x
a=x rads
a6= 4x rads
S6 = 6/2 (2(x) + 5d)
We know that S6 = 2pi
2pi = 6x + 15d ----1
a6 = a + 5d
4x = x + 5d
d=3x/5 ----2
Put 2 in 1 and you should get the value of x.
The perimeter of the smallest sector = rx + r + r
Yah thats my question , How can I do that?Find g-1(x) and replace x by 3.
Does anyone know how to differentiate this? Thanks
y=4-3sinxYah thats my question , How can I do that?
isnt this the question?Here's the answer
Ah man thats so simple! Lol tnx a lot!!y=4-3sinx
3sinx=4-y
sinx=4-y /3
x=sin-1(4-y/3)
g-1(3) = sin-1(4-3/3)
g-1(3) = 0.340
To find derivatives of equations like this one, its best to break it up.Does anyone know how to differentiate this? Thanks
okay correct me if I am wrong but AB=OB-OA right?Ahhh No problem !!
Prayers Needed
I gave the same answer But I didn't simplify it yours is long , just simply seperate 1/pi frn the equation and then find the derivative and put back 1/pi againTo find derivatives of equations like this one, its best to break it up.
A= [(pi x^2 +4x^2) / pi] - (160x/pi) + (1600/pi)
Simplifying further,
A = [ x^2 + {(4x^2)/pi}] - 160x/pi + 1600/pi
dA/dx = 2x + 8x/pi -160/pi
How do we get it in this form though?To find derivatives of equations like this one, its best to break it up.
A= [(pi x^2 +4x^2) / pi] - (160x/pi) + (1600/pi)
Simplifying further,
A = [ x^2 + {(4x^2)/pi}] - 160x/pi + 1600/pi
dA/dx = 2x + 8x/pi -160/pi
I think the 'long' method reduces the chances of errors because everything is kinda 'opened'. Plus, I am sure you've heard the saying "Old habits die hard".I gave the same answer But I didn't simplify it yours is long , just simply seperate 1/pi frn the equation and then find the derivative and put back 1/pi again
If the question asked you to get it in this form, then my method is not suitable. You should use the formal method just like Most_UniQue did.How do we get it in this form though?
Thanks
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