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Can you please show me how you did it step wise if you have timeIs the answer (2x(pi +4) -160)/pi?
Thanks
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Can you please show me how you did it step wise if you have timeIs the answer (2x(pi +4) -160)/pi?
Thank you. How is the formal method done?If the question asked you to get it in this form, then my method is not suitable. You should use the formal method just like Most_UniQue did.
Taking 1/pi common, we get A = 1/pi [ (pi+4)x^2 -160x +1600]Thank you. How is the formal method done?
Try searching the previous pages. This was answered yesterday.View attachment 8724
People please help i cant figure out how to solve the second part. the answer in marking scheme is 7pi/12 but some how i end up getting pi/12.. please help asap i have amy maths exam tomorrow. :'(
this question is from summer 09 qp1.
Dug solved it soonerCan you please show me how you did it step wise if you have time
Thanks
Thank you so much!!!Taking 1/pi common, we get A = 1/pi [ (pi+4)x^2 -160x +1600]
dA/dx = 1/pi[ 2(pi+4) -160]
Wow!! This was less troublesome.
You have to draw the graph of this function which was asked in the previous question . g has an inverse when the graph is 1:1 meaning that for every value of y there is only one value of x therefore A will be 3/2pi.Can someone please solve this???
Function g(x)= 4-3sinx 1/2pi<=x<=A
(i) State the largest value of A for which g has an inverse
Thanks!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_11.pdf
7ii
can someone please help? Thanks
Isn't there a way to do it without the graph?You have to draw the graph of this function which was asked in the previous question . g has an inverse when the graph is 1:1 meaning that for every value of y there is only one value of x therefore A will be 3/2pi.
As far as I know , theres no other way. Didnt you draw the graph which was asked in the previous question?Isn't there a way to do it without the graph?
Yeah I get it now, thank you!As far as I know , theres no other way. Didnt you draw the graph which was asked in the previous question?
My PleasureYeah I get it now, thank you!
for this you need to put 1/3 instead of dy/dx so this equation will behttp://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_11.pdf
7ii
can someone please help? Thanks
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