then I think you've made a silly mistake because instead of subtracting,you've added.yah its perfect !!
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then I think you've made a silly mistake because instead of subtracting,you've added.yah its perfect !!
Hi, can someone urgently help with this q? http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_13.pdf
q3ii
thanks
hi,
how would you find the range of a function in this question
q3ii) http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_13.pdf
THANKS ALOT!!Plugin the values 0 , pi/2 , pi , 3pi/2 , 2pi into the equation and youll get the range. Set your calculator to radian mode.
My Pleasure. Pray for meTHANKS ALOT!!
now I'm fully prepared. Good luck everyone!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
someone please help me with question 6 part (ii), quickly!
We have two equations y= kx^2 +1 and y=kx
Since it says the tangent touches the curve , kx^2+1=kx
Solving this using b^2 - 4ac gives two values of k , k=0 and k=4
Since in the question it says k is a non zero , we ignore k=0 and take k as 4
Now plugin this value into the original equations => y=4x^2 + 1 and y=4x
Solve them simultaneously => 4x^2 + 1 =4x
Therefore x= 1.5 , y=2
yeah okay, got it.
thanks alot.
ERMMM Anyone?
look. when you write in the value of f in f you'll get a fraction in the numerator as well as the denominator. find the l.c.m. of both the numerator and the denominator. the (2x-1) will get cancelled out (from both the numerator and denominator) and then when you simplify you'll be left with 7x/7. cancel the 7s and thus you're left with only an x.ERMMM Anyone?
THNX a LOT!!!!(tanx^n+2 tanx^n)dx substitute tanx = u
(u^n+2 + u^n)dx now du = sec^2x dx
so when substituting du will give
(u^n+2 + u^n)/sec^2x du
now use identity sec^2x = 1+ tan^2x .. means (1 + U^2)
substitute this value of sec^2x in the eq. above
(u^n+2 + u^n)/ (1 + U^2)du now take U^n in numenator
U^n (U^2 + 1 )/ (1 + U^2)du now cxancel (U^2 +1)
u wil get a simple eq. (U^n)du
inegrate it
u^n+1 / n+1 now convert back into original by substiuting tanx
tanx^n+1/ n+1 put the limits
tan(45)^n+1/n+1 tan45 = 1 so... 1^n+1 = 1
it wil be as follows 1/ n+1
f'(x) is the derivative and f-1(x) is the inverse.what is the difference in f '(x) and??? 9709/13/m/J/11 question 10
oh yeah.. ryt..i forgot that. thankyou =)f'(x) is the derivative and f-1(x) is the inverse.
1.do the LCM in the numerator as well as in the denominator .
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