Mathematics: Post your doubts here!

[2pac]

yah its perfect !!

then I think you've made a silly mistake because instead of subtracting,you've added.

 

[Mosamali]

hi,
how would you find the range of a function in this question
q3ii) http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_13.pdf

 

[Helpneeded007]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_12.pdf
I cant understand how to solve question 6?
Please Help.
Thanks alot.

 

[rash1233]

Hi, can someone urgently help with this q? http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_13.pdf
q3ii
thanks

 

[Most_UniQue]

Hi, can someone urgently help with this q? http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_13.pdf
q3ii
thanks

hi,
how would you find the range of a function in this question
q3ii) http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_13.pdf

Plugin the values 0 , pi/2 , pi , 3pi/2 , 2pi into the equation and youll get the range. Set your calculator to radian mode.

 

[rash1233]

Plugin the values 0 , pi/2 , pi , 3pi/2 , 2pi into the equation and youll get the range. Set your calculator to radian mode.

THANKS ALOT!!
now I'm fully prepared. Good luck everyone!

 

[Most_UniQue]

THANKS ALOT!!
now I'm fully prepared. Good luck everyone!

My Pleasure. Pray for me

 

[Most_UniQue]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf
someone please help me with question 6 part (ii), quickly!

We have two equations y= kx^2 +1 and y=kx

Since it says the tangent touches the curve , kx^2+1=kx

Solving this using b^2 - 4ac gives two values of k , k=0 and k=4

Since in the question it says k is a non zero , we ignore k=0 and take k as 4

Now plugin this value into the original equations => y=4x^2 + 1 and y=4x

Solve them simultaneously => 4x^2 + 1 =4x

Therefore x= 1.5 , y=2

 

[maryamshake94]

We have two equations y= kx^2 +1 and y=kx

Since it says the tangent touches the curve , kx^2+1=kx

Solving this using b^2 - 4ac gives two values of k , k=0 and k=4

Since in the question it says k is a non zero , we ignore k=0 and take k as 4

Now plugin this value into the original equations => y=4x^2 + 1 and y=4x

Solve them simultaneously => 4x^2 + 1 =4x

Therefore x= 1.5 , y=2
yeah okay, got it.
thanks alot.

 

[robotic94]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_12.pdf

question 6 i
View attachment 8782

ERMMM Anyone?

 

[Most_UniQue]

ERMMM Anyone?

ff(x) = ((x+3)/(2x-1)+3) / (2((x+3)/(2x-1)) -1)

= ((x+3+3(2x-1))/(2x-1)) / ((2x+6-1(2x-1))/(2x-1)

The two (2x-1) cut out giving 7x/7 => x

 

[maryamshake94]

ERMMM Anyone?

look. when you write in the value of f in f you'll get a fraction in the numerator as well as the denominator. find the l.c.m. of both the numerator and the denominator. the (2x-1) will get cancelled out (from both the numerator and denominator) and then when you simplify you'll be left with 7x/7. cancel the 7s and thus you're left with only an x.

 

[usmiunique]

(tanx^n+2 tanx^n)dx substitute tanx = u

(u^n+2 + u^n)dx now du = sec^2x dx

so when substituting du will give


(u^n+2 + u^n)/sec^2x du
now use identity sec^2x = 1+ tan^2x .. means (1 + U^2)

substitute this value of sec^2x in the eq. above



(u^n+2 + u^n)/ (1 + U^2)du now take U^n in numenator

U^n (U^2 + 1 )/ (1 + U^2)du now cxancel (U^2 +1)
u wil get a simple eq. (U^n)du
inegrate it
u^n+1 / n+1 now convert back into original by substiuting tanx

tanx^n+1/ n+1 put the limits
tan(45)^n+1/n+1 tan45 = 1 so... 1^n+1 = 1


it wil be as follows 1/ n+1

THNX a LOT!!!!
cant believe the thing bugging me was this simple!

 

[cHeStEr]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_12.pdf

8i and ii
9i
5i
4ii
10a

 

[Gémeaux]

what is the difference in f '(x) and

??? 9709/13/m/J/11 question 10

 

[Dug]

what is the difference in f '(x) and

??? 9709/13/m/J/11 question 10

f'(x) is the derivative and f-1(x) is the inverse.

 

[Gémeaux]

f'(x) is the derivative and f-1(x) is the inverse.

oh yeah.. ryt..i forgot that. thankyou =)

 

[Aqsa Mohd]

some one plzz helpp me out with dis .. :S
oct/nov 2010 p12 question num 11 .. how to do it ..

 

[cHeStEr]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_12.pdf

question 6 i
View attachment 8782

1.do the LCM in the numerator as well as in the denominator .
in the numerator You'll get something like this ---> ((x+3)+(6x-3)) divided by 2x-1 (which is the LCM of the numerator)
in the denominator you'll get something like this ---> ((2x+6)-(2x+1)) divided by 2x-1 ( which is the LCM of the denominator )
2. both the LCMs gets cancelled therefore, numerator remains as ---> (x+3)+(6x-3) and the denominator as ---> (2x+6)-(2x+1)
3. Solve it ..... you'll get the numerator as 7x and denominator as 7 , which is equal to x.



Hope this helps.

 

[user]

Assalamoalaikum wr wb!!

Can someone plz tell me Q: 1 (ii) of http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf

jazakAllah khairen...