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(i) : gf(x) --> U take f(x) and then U replace in g(x)
f(x) = 2x + 1
g(x) = (2x - 1)/ (x +3)
gf(x) = (2(2x+1) + 1) / ((2x + 1) +3)
= (4x + 3) / (2x + 4)
Now, gf(x) = x
that is, (4x +3) / (2x +4) = x
4x + 3 = 2x^2 + 4x
2x^2 - 3 = 0
x ^ 2 = (3/2)
x = *root* (3/2)
(ii) : To find f inverse, U let the function f(x) to be equal to y
y = f(x)
y = 2x + 1
Now make x the subject of formula
x = (y -1)/ 2
Therefore f inverse : (x - 1)/2 (U replace the y and make it become x)
For g(x)
y = g(x)
(2x - 1)/ (x +3) = y
2x -1 = xy + 3y
2x - xy = 3y + 1
(2 - y)x = 3y + 1
x = (3y +1)/(2 - y)
Therefore g inverse : (3x +1) / (2 - x)
(iii) To sketch the graphs, first U sketch the graph of f(x).. (I believe this one is quite easy)
Now for the inverse, all that we have to do is to reflect the graph in the line y = x.
The reflected part will show the graph of f inverse relative to f(x).
Note : Any calculations were done mentally so am not sure if the answers are correct but I've explained all my workings... Hope it helps.
Well... Are the answers correct?Waaaaoooww ! Mentally ? You are good !
Thanks
Which num.?can somebody help me with this!!like i like the way in which whitecorp does bt anyone else!!like minato112 and leadingguy woould be appreciated!!plzzzzzzzzzzzzzzzzzzz
6th one firstWhich num.?
6th one first
Yo can someone plz help me with this question ( show steps ty):
solve the equation : 2 sin^2(x) -cos x - cos^2(x) 0<x<360
No prob! What matters is that the answer is rightHey minato112 u rock!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!for solving so damnnnn fast!!!
Yeaaaahhhh ! You are too good man !Well... Are the answers correct?
Oh well im not too good... What matters as I already said above is that the answers are rightYeaaaahhhh ! You are too good man !
ty a lot but i missed the question...the question is same expect with the addition of a sin x at the cos x place..its like : 2 sin^2(x) - sin x cos x - cos^2(x) 0<x<360
srry again but i got a lil question..in ur answer uve sent me for the 2 sin^2(x) - cos x - cos^2(x)..uve write cos inverse of 1 is equal to 48.2 ( by sending cos inverse on the other side and 131.8 on the other side..it gives u cos inverse of 1 as 48.2...my calculator give me for cos inverse of 1...0 ..ive done something wrong? again thanks for the fast answer
ok ty..iam looking forward to the other one ( 2 sin^2(x) - sin x cos x - cos^2(x) 0<x<360 ) ty in advanceOh yea srry I took cos inverse of (2/3) instead of cos inverse of 1. Urs is fine.
Here you go, the full solutions for your 1st order differential equation problem.
Hope it helps. Peace.
Well srry for l8 rep., was busy yesterD.ok ty..iam looking forward to the other one ( 2 sin^2(x) - sin x cos x - cos^2(x) 0<x<360 ) ty in advance
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