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If you draw this on the number line //ok i got the roots -7/3 and -3 but how did u conclude that x is greater than -7/3 and less than -3
replace cotx with cosx/sinx ie ( 1/ tanx )View attachment 36253
Sup guys?
If anyone can solve this part, from RHS to the LHS, I'd find it epically awesome. Been trying to solve it (Right to Left) since ages and it's drivin' me mad!
So give it a shot. Every shot is appreciated.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_31.pdf
Please help me with qn no. 9(i).. I have no idea of what to do. I'll be grateful for any help provided
Thanks
Thanx but I got the answer this way.
I want to solve the identity from RHS to LHS, but I keep getting stuck.
So you gotta divide the graph into three (equal) intervals, from x = 0 to π/4.Trapezium rule ,
i continously get it as 1.15 but the answer is 0.98
any help?
i tried , but i didnt get itHey thanx for the effort bro, but I've no prob in solving it from LHS to RHS... I wanna solve it from RHS ie cosec2x to the LHS.
from part(i) ..Rsin(A+b)
Ah got it now. Thanx loads!from part(i) ..Rsin(A+b)
we know that greatest ( maximum ) value of sin function is 1 which happens when teta is 90 degree
The gradient of this function can be found by the first derivative.View attachment 36280
4 (ii) If anyone could give a sketch of what's to be done...
Hmm... k you've slightly confused me. I get what you mean but... doesn't setting the first derivative to zero give us the x-coordinate of vertex? And putting this value into the second der. show nature of the vertex? Uhh...The gradient of this function can be found by the first derivative.
Find the vertex of this function by taking the second derivative, and setting it equal to zero.
Fill in this value ( x value of vertex ) into the first derivative to find the y-value of the vertex.
Take the third derivative to find out if that vertex is a minimum or a maximum.
The third derivative will be always positive which shows it will be never negative
i am not sure correct me if i am wrong
if this way confuses you ,Hmm... k you've slightly confused me. I get what you mean but... doesn't setting the first derivative to zero give us the x-coordinate of vertex? And putting this value into the second der. show nature of the vertex? Uhh...
Anyway, after this - finding nature of vertex (Assuming the point is a minimum)- what do we do?
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