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help bros answer is x is less than or equal to -1
Bring -|x+1| to the right side
|1-x| = 2 + |x+1| now square both sides.
(1-x)^2 = [ (2) + (x+1) ]^2
Note: Treat [ (2) + (x+1) ]^2 as (a+b)^2 where a = 2 nd b = (x+1)
So you get, (1)^2 + (x)^2 -2(1)(x) = (2)^2 + (x+1)^2 +2(2)(x+1)
1 + x^2 - 2x = 4 + x^2 + 1 + 2x + 4x + 4
Simplify, 8x = -8
x = -1