We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Oh yes I've looked into it your value for b is correct
Yes, that's the thing, I think your answer is correct tho,
Alright thanks!!Yes, that's the thing, I think your answer is correct tho,
I'll ask my mom's friend to help out so we could be sure, and I'll inform you
You can find them at gceguide.com
Heey I still haven't got a reply from my moms' friend but I was thinking that I think the question is pretty simple like they said domain has to be greater than 1, therefore it can't be 0, and actually we were confused with what domain to take but since they said x>1 and we know f(x) range will be the domain of g(x) so if we place f(x)>1 you won't get a value for it except when f(x)>3, therefore, its obvious to say that x can only be 3 and up to infinity, and if you try values greater than 3 you'll find it tends towards 0, so I think its right to say 0<gf(x)<1,
It's less than 1 not greater...if we use x<1 then the range would be 0<gfx<2/3
No we have to use the domain of f(x)
Yo they're saying the domain of g(x) has to be x>1, f(x) range is the domain of g(x), in other words, f(x)>1
Here I've got the answers
why are they taking the domain of gf(x) to be lesser than 1?
We have to take the domain of the inner function which is f
This doesn't become a composite function like that! isn't the range of f(x) the domain of g(x)??
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now
