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- 112
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thank you so muchhhh
You are welcomethank you so muchhhh
In order to apply logarithm on 1/y^3 the derivative of y^3 should be present in the numerator then we can use it.I had a question though......why are you not doing ln y^3??
Oh ok.....so for example it was 2/y^3.........we could write this as 2ln(y^3)In order to apply logarithm on 1/y^3 the derivative of y^3 should be present in the numerator then we can use it.
No ....derivative of y^3 is 3y^2 this should be present.Oh ok.....so for example it was 2/y^3.........we could write this as 2ln(y^3)
So 3y^2 should be the numerator?.......Always??No ....derivative of y^3 is 3y^2 this should be present.
Liek for all denominators....the numerator should be a derivative in order to use ln?So 3y^2 should be the numerator?.......Always??
yesSo 3y^2 should be the numerator?.......Always??
correctLiek for all denominators....the numerator should be a derivative in order to use ln?
Thanks <3correct
You are welcomeThanks <3
For remembrance it's given on the formula sheetThanks <3
Thanks.....once again!!!For remembrance it's given on the formula sheet
No problemThanks.....once again!!!
can anyone please send me the working of feb19 q3?