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Mathematics: Post your doubts here!

daviruss

daviruss

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assalamu 3alaikom guys, iam going to sit for my AS exam in oct/nov 2012 Mathematics (P1,M1) and seems that every thing is going great el7amdolilah, but iam just having trouble in trying to calculate the surface area or the volume of a figure , for example when a question comes asking abt to show that A= blah blah :p. and that find h in terms of r, for example , and then a diffrentiation question , the diff question is easy but the hardest thing for me is to find the SA so please help me! iam going to sit for my exam soon. Can u till me any tip for how to prepare for the math AS , P.S. i do solve PP's
 
parthrocks

parthrocks

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parthrocks said:
A question from statistics 2 chapter:-sampling in statistics 2

can sum1 plzz show me the steps!!and is Continuity correction required?
minato112
whitecorp
leadingguy
leosco1995
nightrider1993
smzimran

5. The masses of kilogram bags of flour produced in a factory have a normal distribution
with mean 1.005 kg and standard deviation 0.0082 kg. A shelf in a store is loaded with
22 of these bags, assumed to be random sample.
(a) Find the probability that a randomly chosen bags has mass less than 1 kg.
(b) Find the probability that the mean mass of the 22 bags is less than 1 kg
State, giving a reason, which of the above answers would be little changed if the
distribution of masses were not normal.
Click to expand...
Anyone reply plzzzzzz need it urgently
 
giligili

giligili

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minato112 said:
Well srry for l8 rep., was busy yesterD.

=> 2 sin^2(x) - sin x cos x - cos^2(x) = 0
=> (Divide by cos^2 (x) everywhere) => 2 tan^2 (x) - tan x - 1 = 0
=> (2 tan x + 1) (tan x - 1) = 0
=> tan x = (-1/2) or tan x = 1

tan x = (-1/2) :

x = 180 + [*tan inverse* (1/2) ] = 206.6
or x = 360 + [*tan inverse* (1/2) ] = 333.4

tan x = 1 :

x = *tan inverse* (1) = 45
or x = 180 + [*tan inverse* (1) ] = 225

Hope It helps.
Click to expand...
ty very much for the reply late or not :) much appreciated
 
U

unique840

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jeffreylpy said:
Need help plz for nov 2011 paper 33 no 6(ii) could you do it for me plz.. how to find the eqn of the circle and the no 4 too. i am stuck somewhere.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf
Click to expand...
u have w. u can find out w^2
u have both the points. take their midpoint which will be the centre of the circle. that will be replaced by a and b. thn find the modulus of the 2 points which will be the distance between them. that will be the circumference. divide it by 2 to get the radius. radius will be k.
 
NouranAyman

NouranAyman

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daviruss said:
assalamu 3alaikom guys, iam going to sit for my AS exam in oct/nov 2012 Mathematics (P1,M1) and seems that every thing is going great el7amdolilah, but iam just having trouble in trying to calculate the surface area or the volume of a figure , for example when a question comes asking abt to show that A= blah blah :p. and that find h in terms of r, for example , and then a diffrentiation question , the diff question is easy but the hardest thing for me is to find the SA so please help me! iam going to sit for my exam soon. Can u till me any tip for how to prepare for the math AS , P.S. i do solve PP's
Click to expand...
heyy!! :D Im sitting for this too in November :/ I hope all the best for both of us! Dont worry this kind of questions are easy... You can show me one question and i can help you solving it as much as i can and in return i need u to help me with the domain and range and trignoemty graphs , i dont know how to solve those... and can you tell me what year are u in now?? :D
 
Minato112

Minato112

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Yousif Mukkhtar said:
Guys got a question for this paper:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_1.pdf
Question 5. How to get C here? I understood everything else.

Can you explain the vector method mentioned there?
Click to expand...
In fact there's a simple method where U can find C.

The method is:

The sum of x coordinates of two opposite points is equal to the sum of the x coordinates of the other two opposite. The same for y coordinates.

For U to better understand it:
Assuming the point A is (a, 0). (well U know the real value, I took it to be (a, 0) cuz' I dunno its real value)

Now take the point C to be (x , y)

Therefore, applying the above principle leads U to:
a + x = 2 + 6 = 8
Therefore x = 8 - a

Same for y:
0 + y = 10 + 2
Therefore y = 12

There the point C is ( 8-a , 12)

Hope it helps. :)
 
whitecorp

whitecorp

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iKhaled said:
can someone please explain to me question 9 ii) paper 1 october november 2009

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_11.pdf
Click to expand...

The key idea is to first find the unit vector representing vector AC, and since this would have a magnitude of 1, we can simply multiply it by a factor of
30 to scale it to the required length. In other words, the required vector is simply equal to 30* unit vector of AC.

Hope this helps. Peace.
 
daviruss

daviruss

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NouranAyman said:
heyy!! :D Im sitting for this too in November :/ I hope all the best for both of us! Dont worry this kind of questions are easy... You can show me one question and i can help you solving it as much as i can and in return i need u to help me with the domain and range and trignoemty graphs , i dont know how to solve those... and can you tell me what year are u in now?? :D
Click to expand...
hey man , thx for the reply anyways am a senior, last year bro and i am doing my AS math in november , first of all not easy i have a big problems even though when they ask for radian and stuff am not good at geometry but u can post a question here and i can help solve and ill send the question as an inbox :)
 
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