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Thanx a lot! ..
Second part of the question is pretty easy, you just substitute with 2 in the given equation.
You find minimum/maximum of something by differentiating it, and equating the derived formula to zero. Thus to find the minimum of the GRADIENT you need to differentiate dy/dx. This would be 1-8/x^3 and this would be equal to zero when x = 2 . So how do we decide if it's a minimum or a maximum?
There are various ways, one of them would be substituting in the derived equation with a value smaller than 2 and a value greater than 2. If you do so with x =1 and 3 for example, you'd find that the derived formula changes from a negative(decreasing gradient) to a positive (increasing gradient) i.e. a minimum.
Another method would be simple substitution in the gradient equation. Since it's either a minimum or a maximum at x =2, compare the gradient with any value of x and that of 2 ( The second part of the question ), if the gradient of 2 is smaller then it must be a minimum, and that's the case given.