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Mathematics: Post your doubts here!

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Thanx a lot! :D..

Second part of the question is pretty easy, you just substitute with 2 in the given equation.

You find minimum/maximum of something by differentiating it, and equating the derived formula to zero. Thus to find the minimum of the GRADIENT you need to differentiate dy/dx. This would be 1-8/x^3 and this would be equal to zero when x = 2 . So how do we decide if it's a minimum or a maximum?

There are various ways, one of them would be substituting in the derived equation with a value smaller than 2 and a value greater than 2. If you do so with x =1 and 3 for example, you'd find that the derived formula changes from a negative(decreasing gradient) to a positive (increasing gradient) i.e. a minimum.

Another method would be simple substitution in the gradient equation. Since it's either a minimum or a maximum at x =2, compare the gradient with any value of x and that of 2 ( The second part of the question ), if the gradient of 2 is smaller then it must be a minimum, and that's the case given.
 
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I need help ppl...
2007 may-jun p1 q11 (i),(ii)n (iii)
for (i) i jus wanna kno the part that says how do u kno its a decreasing function and for(ii) i jus wanna kno how to find the domain
thanx in advance
 
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Second part of the question is pretty easy, you just substitute with 2 in the given equation.

You find minimum/maximum of something by differentiating it, and equating the derived formula to zero. Thus to find the minimum of the GRADIENT you need to differentiate dy/dx. This would be 1-8/x^3 and this would be equal to zero when x = 2 . So how do we decide if it's a minimum or a maximum?

There are various ways, one of them would be substituting in the derived equation with a value smaller than 2 and a value greater than 2. If you do so with x =1 and 3 for example, you'd find that the derived formula changes from a negative(decreasing gradient) to a positive (increasing gradient) i.e. a minimum.

Another method would be simple substitution in the gradient equation. Since it's either a minimum or a maximum at x =2, compare the gradient with any value of x and that of 2 ( The second part of the question ), if the gradient of 2 is smaller then it must be a minimum, and that's the case given.

Thanx! :D
 
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Can sum1 plz help with the foll questions:
2007 oct-nov p1 q4(ii),(iii)
2008 oct-nov p1 q2, q9(iii)
plz plz help me:cry:
thanx in advance
 
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can someone help me with this question;

- Functions f and g are defined by

f(x)=4x-2k ...... g(x)= 9/(2-x)

(i) find the values of k for which the equation fg(x)=x has two roots
(ii) determine the roots of the equation fg(x)=x for the values of k found in part (i)

the answers are: (i) k=5 or k=-7
(ii) x=-4 or x=8
 
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can someone help me with this question;

- Functions f and g are defined by

f(x)=4x-2k ...... g(x)= 9/(2-x)

(i) find the values of k for which the equation fg(x)=x has two roots
(ii) determine the roots of the equation fg(x)=x for the values of k found in part (i)

the answers are: (i) k=5 or k=-7
(ii) x=-4 or x=8



i) you have to solve them simultaneously and then use (b^2 - 4ac) > 0

ii)replace the values of k and form the composite function of fg(x) and equate it to x. Solve for x. You will get the answers :)
 
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i) you have to solve them simultaneously and then use (b^2 - 4ac) > 0

ii)replace the values of k and form the composite function of fg(x) and equate it to x. Solve for x. You will get the answers :)
thanks alot mess :)
 
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i) you have to solve them simultaneously and then use (b^2 - 4ac) > 0

ii)replace the values of k and form the composite function of fg(x) and equate it to x. Solve for x. You will get the answers :)
thanks alot mess :)
 
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SALAAM BHAIJAAN. PLEASE HELP ME FOR PART (iii). pLEASE.
One turn of a game is as follows. Two coins are tossed. If the exposed faces of the two coins are the same as each other, then BOTH are tossed for a second time and the turn ends. Otherwise, the turn ends after the first toss of the coin. The scores, X obtained in the turn, is equal to the total number of HEADS exposed during that turn.

(i) I have already constructed the prob. distribution of X. P(X=3)=1/8 and P(X=1)=5/8.
(ii) Already calculated. E(X)=1.5 Var(X)=1
(iii) The scores obtained two randomly chosen turns are X1 and X2. E(X1 - X2)=0. PLEASE HELP ME IN FINDING OUT P(X1=X2).
 
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Can someone give me the full solution for these?
9709/03/O/N/04 - Question 2
9709/03/M/J/08 - Question 2
 
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can someone help explain how to find the volume in Q 10(iii) and also help explain how y^2=1+2x becomes x=1/2(y^2-1) http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_11.pdf


Since it asks to find the volume about the y-axis, u have to make the equation of the curve becomes in terms of y.

y^2=1+2x
2x = y^2 - 1
x = (y^2 - 1)/2

Now U use the formula to find the volume :

*pie* *integration* [(y^2 - 1)/2]^2 from 0 to (y-coordinate of B)

You should get the answer. Hope it helps.
 
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