Mathematics: Post your doubts here!

[xino9512]

Hi I am doing my A2s and I can't do this question please help me!!
oct/nov 10 p.32 q.9
thanks in advance!

 

[Maz]

Can someone help me with question 6 May/June 2013 Paper 31

6 i) Seeing that PQ is perpendicular to the plane, PQ is therefore a normal to the plane.

A = midpoint of PQ= (OP+OQ)/2 . (7i+(-5i) +7j+j - 5+k)/2 = i +4j -2k
PQ = q-p = -5i -7i +j-7j +k+5k = -12i -6j+6k

r.n = a.n [equation of a plane]
(xi+yj+zk).(-12i -6j+6k) = (i +4j -2k).(-12i -6j+6k)
-12x-6y+6z = -48
12x+6y-6z = 48

ii) [this would be easier to solve if you make a diagram] [there are two methods of solving this, i'll be showing one]

First find "B"

Since PB is parallel to x-axis its directional vector is "i" = (1 ,0 ,0)
Therefore, The vector equation is=

r=(7i +7j -5k) + t(i)
r=((7+t i)+ 7j -5k)

Put this in the plane equation since PB is intersecting with the plane at B.
12(7+t) +6(7) -6(-5) = 48
t= -9
Put this in the earlier vector equation, the answer is the value of B = (-2,7,-5)

Use the distance equation to the the distance from A to B.

 

[jainam]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s04_qp_3.pdf
9 ii)
please reply as soon as possible

 

[kaushar]

i need help for paper 32 may/june 2013 plzz question 10
plzzz i have an exam 2morrow

 

[jainam]

i need help for paper 32 may/june 2013 plzz question 10
plzzz i have an exam 2morrow

send the link of the paper

 

[kaushar]

The points A and B have position vectors 2i − 3j + 2k and 5i − 2j + k respectively. The plane p has
equation x + y = 5.
(i) Find the position vector of the point of intersection of the line through A and B and the plane p.
(ii) A second plane q has an equation of the form x + by + cÏ = d, where b, c and d are constants.
The plane q contains the line AB, and the acute angle between the planes p and q is 60Å. Find
the equation of q.


this is the question..

 

[kaushar]

x + by + cz = d
sory for copy and paste

 

[Tkp]

can some1 help me in may june 12 (32) ques 5

 

[6Astarstudent]

can some1 help me in may june 12 (32) ques 5

dy/dx= e^(2x+y) = e^(2x) * e^y
e^(-y) dy = e^(2x) dx
-e^(-y) = 0.5e^(2x) + c
substitute x=0 y=0
-1 = 0.5 + c c= -1.5
-e^(-y) = 0.5e^(2x) - 1.5
e^(-y) = -0.5e^(2x) + 1.5
-y = ln(3-e^(2x)/2)
y = ln(2/(3-e^(2x))

 

[$~SauD~$]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_32.pdf

Question 10. part 3.

 

[HongYue]

http://olevel.sourceforge.net/papers/9709/9709_s13_qp_31.pdf
Question 7 part (ii)
Thx.

 

[Tkp]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_32.pdf

Question 10. part 3.

thats my prblm 2 also

 

[Tkp]

dy/dx= e^(2x+y) = e^(2x) * e^y
e^(-y) dy = e^(2x) dx
-e^(-y) = 0.5e^(2x) + c
substitute x=0 y=0
-1 = 0.5 + c c= -1.5
-e^(-y) = 0.5e^(2x) - 1.5
e^(-y) = -0.5e^(2x) + 1.5
-y = ln(3-e^(2x)/2)
y = ln(2/(3-e^(2x))

thnks

 

[$~SauD~$]

thats my prblm 2 also

If i get solution, i will post it up here dw

 

[$~SauD~$]

thats my prblm 2 also

If i get solution, i will post it up here dw

 

[Maz]

Hey, could someone please post notes for complex numbers and vectors. Especially complex- i'm more or less lost... Please...

 

[MrMe001]

hi, I need the solution for May/June 2013 p33 Q7

help pls. URGENT

 

[MrMe001]

hi, I need the solution for May/June 2013 p33 Q7

help pls. URGENT

 

[Kumkum]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_32.pdf

Question 10. part 3.

thats my prblm 2 also

here's the solution to 10 part 3 https://www.xtremepapers.com/community/threads/a-maths-doubt.24710/

 

[Tkp]

here's the solution to 10 part 3 https://www.xtremepapers.com/community/threads/a-maths-doubt.24710/

thnks