Mathematics: Post your doubts here!

[Rutzaba]

Okay. For 'Q7' I'll find the mid-point of AB than the gradient of AB and use it to find the equation of the perpendicular bisector. Can you tell how will i find the co-ordinate of D"

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w05_qp_1.pdf

First u will find the midpoint of AB and the gradient of AB then the eq of line AB
then find the equation of line BC then solve simultaneously

 

[biscuitbiscuit]

First u will find the midpoint of AB and the gradient of AB then the eq of line AB
then find the equation of line BC then solve simultaneously

Thanks. For 'Q6' how to do the second sub-part, http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s07_qp_1.pdf

 

[Rutzaba]

see this http://s1275.photobucket.com/user/Rutzaba/media/mathies_zpsf8d7677a.png.html

 

[Rutzaba]

Thanks. For 'Q6' how to do the second sub-part, http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_1.pdf

y dun u refer to the answer paper ?

 

[biscuitbiscuit]

y dun u refer to the answer paper ?

Its okay if u got tired of answering

 

[Rutzaba]

Its okay if u got tired of answering

nah sweety its not that. if u r getting the concept u shud be able to solve it urself na?
thats how u learn

 

[biscuitbiscuit]

after you find out the equation of BC which turns out to be 3y+2x=20, substitute y=0 for C. So the coordinates are C(10,0). To find D, we know that AB is parallel to CD. So count the number of steps (i.e from A-B, the x-coordinate moves from -2 to 2, and y-coordinate from 8 to 14. So similarly, we move 4 units right and 6 units up from C to D) Voila!.... D(14, 6)

Thanks

 

[biscuitbiscuit]

nah sweety its not that. if u r getting the concept u shud be able to solve it urself na?
thats how u learn

Its easy in the book but when it comes to past papers I am blank

 

[saadgujjar]

3cos(2x-Y)+4sin(2x-Y)=2
find x 0 to 2pi
Y is theta

 

[Rutzaba]

Its easy in the book but when it comes to past papers I am blank

it shudnt be like that buddy. thses questions are quiet simple

 

[Rutzaba]

3cos(2x-Y)+4sin(2x-Y)=2
find x 0 to 2pi
Y is theta

do this by using the opening formulas for sin( alpha- theta)
and cos(alpha- theta)

 

[saadgujjar]

do this by using the opening formulas for sin( alpha- theta)
and cos(alpha- theta)

plz solve..

 

[ahmed abdulla]

Hello .. can u help me with this ...
Show that ,
integral of tan2x =1/2 Insec2x + c

i am not that good in integration ... every time we perform a new thing ! .. is there a specific formula which applies to all integrations .. help

 

[Rutzaba]

plz solve..

have to integrate this?

 

[DumbIdiot]

3cos(2x-Y)+4sin(2x-Y)=2
find x 0 to 2pi
Y is theta

here`re the values of 2x-Y : -0.232, 2.09, 6.05

 

[ahmed abdulla]

integrate cos^2(x)

 

[DumbIdiot]

Hello .. can u help me with this ...
Show that ,
integral of tan2x =1/2 Insec2x + c

i am not that good in integration ... every time we perform a new thing ! .. is there a specific formula which applies to all integrations .. help

tan2x = sin2x/cos2x
integration of sin2x/cos2x = -0.5(ln(cos2x)+c = o.5ln(cos2x)^-1 +c = 0.5ln(sec2x) +c

integrate cos^2(x)

use the double angle formula for this one
cos^2(x) = (cos2x+1)/2

 

[Lama AN]

question 2 - Nov 2004 - mechanics 1 ( paper 4)

i found out (i) so easily . but can anyone explain for me part (ii) ?

 

[saadgujjar]

here`re the values of 2x-Y : -0.232, 2.09, 6.05

tell me procedure..

 

[saadgujjar]

here`re the values of 2x-Y : -0.232, 2.09, 6.05

tell me procedure..