Mathematics: Post your doubts here!

[sitooon]

sitooon here i hop this helps this is all i can found

Can you check its validity , it doesnt open with me !

 

[ZaqZainab]

Can you check its validity , it doesnt open with me !

https://www.xtremepapers.com/community/threads/maths-notes-p1-p2-m1-m2-and-s1.9180/

 

[sitooon]

https://www.xtremepapers.com/community/threads/maths-notes-p1-p2-m1-m2-and-s1.9180/

Thanks for you searching , but its not useful !

 

[Igcse stuff]

found those probzz ....
solve em up now ..

ahmed abdulla

Here you go

 

[tanweera]

Maths p3 nov 08 solution plzzz

 

[tanweera]

November 2008 p3 help plzz

 

[mania _ manal]

Tha

P(X = 0) = 1/10 (given)
remaining integers are 7 from the set and the probability is to be divided equally among them
so the probability of one of the remaining 7 integers = 1 - (1/10) divided by 7 = (9/10) / 7 = 9/70

i) P(X<2) = P(X = - 2) + P(X = - 1) + P(X = 0) + P(X=1)
= 9/70 + 9/70 + 1/10 + 9/70 = 0.486

ii) the probability distribution table looks like

x - 2 - 1 0 1 2 3 4 5
p(X=x) 9/70 9/70 1/10 9/70 9/70 9/70 9/70 9/70

now calculate the variance using the formula
E(X^2) - ((E(X))^2

iii) we are going from the negative of a positive number to its twice. so let's check the possibility of a number existing in negative which is - 2 or - 1
so now first possibility
let a be 1 so probabilities should be added from - 1 to 2(1) = 2

P(X=-1) + P(X=0) + P(X=1) + P(X=2)
= 9/70 + 1/10 + 9/70 + 9/70 = 17/35 (shown)[

 

[mania _ manal]

Thanks alott can u help me in ths too http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_63.pdf Q2 ii)

 

[mania _ manal]

T

P(X = 0) = 1/10 (given)
remaining integers are 7 from the set and the probability is to be divided equally among them
so the probability of one of the remaining 7 integers = 1 - (1/10) divided by 7 = (9/10) / 7 = 9/70

i) P(X<2) = P(X = - 2) + P(X = - 1) + P(X = 0) + P(X=1)
= 9/70 + 9/70 + 1/10 + 9/70 = 0.486

ii) the probability distribution table looks like

x - 2 - 1 0 1 2 3 4 5
p(X=x) 9/70 9/70 1/10 9/70 9/70 9/70 9/70 9/70

now calculate the variance using the formula
E(X^2) - ((E(X))^2

iii) we are going from the negative of a positive number to its twice. so let's check the possibility of a number existing in negative which is - 2 or - 1
so now first possibility
let a be 1 so probabilities should be added from - 1 to 2(1) = 2

P(X=-1) + P(X=0) + P(X=1) + P(X=2)
= 9/70 + 1/10 + 9/70 + 9/70 = 17/35 (shown)

hanks aloot can u help me in ths too http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_63.pdf Q2 ii)

 

[yousef]

Hello every one , help needed in two question ,,
question 9 http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf

question 10 i & iv http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_31.pdf

 

[x-gamer-x]

can some one explain me this

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_41.pdf

Q 3

thank u

(MECHANICS 1)

 

[Supernatral]

PLEASE! I need help, Is there is a list of laws and rules for Pure 1 to memorize so I can solve in exams because I'm screwed?!

 

[M.Fazy]

Hello everyone , Tomorrow is my Mechanics mocks paper (M1) , and I am quite tensed
I got everything as a concept rather then the application of Integration !!!!!
I really need help with , why u use integration ?

In this paper " http://adf.ly/i6ULe " go to Question no:6 part iii and tell me what happened there ._________."
I am very confused with that solution , I totally don't understand the point of that question's iii part. Please Answer asap because after 7 Hours from now , It's my paper.

 

[tompapaya]

hello,everyone.questions in 9709_s11_qp_31 Q8 http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_31.pdf
1)how to show the argu=-0.5pie? i can only use diagram to show that ..
and how to solve the question ii)&iii) ??
THANKS A LOT!!!!

 

[sitooon]

Whats the meaning of ( EE/KE/PE balance ) in M2 ???

 

[tompapaya]

M2! so cool!!!

 

[tompapaya]

Whats the meaning of ( EE/KE/PE balance ) in M2 ???

Whats the meaning of ( EE/KE/PE balance ) in M2 ???

M2!!so cool!!!

 

[sitooon]

M2!!so cool!!!

I didnt get you >?

 

[tompapaya]

I didnt get you >?

what i would like to add here is that M2 is too difficult for me , so i just choose the S1 to substitute M2. therefore i said "cool"~~

 

[usama321]

can some one explain me this

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_41.pdf

Q 3

thank u

(MECHANICS 1)

NOTE: The tension in the string is equal to T. I am just naming them T1 and T2 so that you can understand them easily, otherwise they are equal.

Resolving forces vertically, there are two forces acting downwards, one is the weight of the ring 8.5N and the other is the component of T2, T2 cos x

One force acting upward which is T1 cos (90-x) which is equal to T1 sin x

thus 8.5 + T2 cosx = T1 sin x

Resolving forces horizontally, there are two forces acting to the left, that are T2 sin x and T1 sin(90-x) which equals T1 cos x.
The other force acting to the right is 15.5 N
Thus
T2 sin x + T1 cosx = 15.5

Now, just put in T for both strings.

Now solve these simultaneously.

T sin x + T cosx = 15.5
T cosx - T sin x = -8.5

2Tcosx = 7
T cos x = 3.5
Similary,
T sin x = 12

Now, rearrange the first equation
x = 3.5/cos x
Put it in the other equation

T sin * 3.5/cos x = 12
3.5T sin x/cos x = 12
sin/ cos = tan
3.5 T tan x = 12

Find the value of x