Mathematics: Post your doubts here!

[Lola_sweet]

In statistics wht does the term 'false zero' mean?

 

[Thought blocker]

In statistics wht does the term 'false zero' mean?

chishtyguy

 

[Lola_sweet]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_13.pdf

How do we solve Q8) ii) and iii) also Q10)ii
also how do we knw if function is decreasing?

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_13.pdf

How do we solve Q8) ii) and iii) also Q10)ii

RoOkaYya G

 

[Dynamite]

http://maxpapers.com/syllabus-materials/mathematics-9709-a-level/attachment/9709_s14_qp_31/
question 7 help needed !!!!!!!!!!11

 

[RoOkaYya G]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w13_qp_13.pdf

How do we solve Q8) ii) and iii) also Q10)ii
also how do we knw if function is decreasing?

RoOkaYya G

showed

 

[Lola_sweet]

showed

Thank u

 

[Thought blocker]

http://maxpapers.com/syllabus-materials/mathematics-9709-a-level/attachment/9709_s14_qp_31/
question 7 help needed !!!!!!!!!!11

RoOkaYya G You gotta solve this. Or should I go for this?

 

[RoOkaYya G]

RoOkaYya G You gotta solve this. Or should I go for this?

u do

 

[Noman.Ahmed]

Help!!

 

[Noman.Ahmed]

SOLUTION PLEASE!!! SOMEONE HELP

 

[RoOkaYya G]

View attachment 49459 SOLUTION PLEASE!!! SOMEONE HELP

cross multiply and then solve simultaneously...ull get value of A B C D
then replce in the equation
(ii)
use answer from (i) to integrate.

 

[awzm guy]

assalamoalaikum !!!!

im currently doing my AS Levels.

i have a dbt in Question no.4 paper 6(statistics 1) 2004 may/june Qp.

 

[Haya Ahmed]

People how to sovle the (iii) part .. thanks

 

[MafaldaC]

Can someone help me please?
4

Particles A and B, ofmasses 0.2 kg and 0.3 kg respectively, are connected by a light inextensible string.

The string passes over a smooth pulley at the edge of a rough horizontal table. Particle A hangs freely

and particle B is in contact with the table (see diagram).

(i) The system is in limiting equilibrium with the string taut and A about to move downwards. Find

the coefficient of friction between B and the table. [4]

A force now acts on particle B. This force has a vertical component of 1.8N upwards and a horizontal

component of X N directed away from the pulley.

(ii) The system is now in limiting equilibrium with the string taut and A about to move upwards.

Find X. [3]
Cant answer question ii and whats the difference of A going down or up?

 

[Thought blocker]

Can someone help me please?
4

Particles A and B, ofmasses 0.2 kg and 0.3 kg respectively, are connected by a light inextensible string.

The string passes over a smooth pulley at the edge of a rough horizontal table. Particle A hangs freely

and particle B is in contact with the table (see diagram).

(i) The system is in limiting equilibrium with the string taut and A about to move downwards. Find

the coefficient of friction between B and the table. [4]

A force now acts on particle B. This force has a vertical component of 1.8N upwards and a horizontal

component of X N directed away from the pulley.

(ii) The system is now in limiting equilibrium with the string taut and A about to move upwards.

Find X. [3]
Cant answer question ii and whats the difference of A going down or up?

abcde credits. (Part ii)
i)
T = F and F = μR
T = μR
From the figure you can see T = 2N and R = 3N and μ = T/R = 2/3

ii)
As the system is in limiting equilibrium, the tension would equal A's weight i.e. 2N.
As A is about to move upwards, B is about to move rightwards. So the frictional force now will be in the same direction as the tension.
First, analyse the vertical forces.
In equilibrium, R + 1.8 = 3. => R = 1.2 N.
Considering forces horizontally, X = 2 + 2/3 (1.2) = 2.8 N.

 

[Thought blocker]

People how to sovle the (iii) part .. thanks

I just know one thing here :
f (x) = sin (x) / x

dy/dx = [ d/dx (sin (x) ) * x - (sin (x) ) * d/dx (x) ] / x²

dy/dx = [ cos (x) * x - (sin (x) ) ] / x²

dy/dx = [ xcos (x) - sin (x) ] / x²

dy/dx = ( x cos (x) / x² ) - ( sin (x) / x² )

dy/dx = ( cos (x) / x ) - ( sin (x) / x² )

 

[Thought blocker]

u do

I am not getting it -_-

 

[RoOkaYya G]

I am not getting it -_-

i cnt also
when i was havin exams i couldnt do it n now u expect me to do it

 

[Thought blocker]

i cnt also
when i was havin exams i couldnt do it n now u expect me to do it

I totally lost my control over vectors.
I need to do that topic again :'(
How can dis happen to me