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Mathematics: Post your doubts here!

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View attachment 53119
Yeah but then how come it doesn't work with chain rule... :/
See if you substitute x=16, the numerator becomes 0, so the whole thing just gives 0 .... thats wrong... have i integrated wrong?
U need to first square the equation given
if y=4x +2
so it becomes y^2=16x^2+16x+4
Now you'll integrate it :)
 
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U need to first square the equation given
if y=4x +2
so it becomes y^2=16x^2+16x+4
Now you'll integrate it :)
Yeah thats the safe way of doing it... but then when you don't expand the bracket it doesn't work... so i was just wondering why it doesn't work... :p
 
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How are we going to do Q2 a part (n)
So long, lemme remember ur name, asma ryt?:p
According to me a = 2 and b = 25
This is how it goes :¬
b - (x - 1)^2
b - (x^2 - 2x + 1)
b - x^2 + 2x - 1
-x^2 + 2x + (b - 1)
We know that c(ax^2 + bx + c) = 24
So b - 1 = 24 ; b 25.
25 - (x - 1)^2
Opening this, we get 24 + 2x - x^2. so a = 2.
 
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Yep thanks can you do Q4 a part too :'(
So long, lemme remember ur name, asma ryt?
According to me a = 2 and b = 25
This is how it goes :¬
b - (x - 1)^2
b - (x^2 - 2x + 1)
b - x^2 + 2x - 1
-x^2 + 2x + (b - 1)
We know that c(ax^2 + bx + c) = 24
So b - 1 = 24 ; b 25.
25 - (x - 1)^2
Opening this, we get 24 + 2x - x^2. so a = 2.
 
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