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GoodHow's prep?
Chem is what I'm worried about most!
Wbu?
BTW Good luck!
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GoodHow's prep?
U need to first square the equation givenView attachment 53119
Yeah but then how come it doesn't work with chain rule... :/
See if you substitute x=16, the numerator becomes 0, so the whole thing just gives 0 .... thats wrong... have i integrated wrong?
Good. Well most of the P1's are quite same so im bit bored doing themGood
Chem is what I'm worried about most!
Wbu?
BTW Good luck!![]()
Yeah thats the safe way of doing it... but then when you don't expand the bracket it doesn't work... so i was just wondering why it doesn't work...U need to first square the equation given
if y=4x +2
so it becomes y^2=16x^2+16x+4
Now you'll integrate it![]()
Thanx
You're welcomeThanx
9x^2 - 12x + 5Hey guys, can anyone help me out with Q3 (i)? Thank you!![]()
Yes. It is allowed. It only does numerical integration and differentiation, therefore it is allowed, it doesn't do symbolic integration/differentiationGuys ..
I have a question is calculator 991EX allowed for paper 1
http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/P3/module.php 1st chapter.In paper 3 how do we obtain the modulus and argument?
Practice this paper : http://themathelp.com/pdf/a level p1.pdf
Just dont look at answers, some are wrong and answers to Q7 is missing.
Just where you feel your answer is not matching the answer, post it here. We'll discuss together.![]()
So long, lemme remember ur name, asma ryt?How are we going to do Q2 a part![]()
So long, lemme remember ur name, asma ryt?
According to me a = 2 and b = 25
This is how it goes :¬
b - (x - 1)^2
b - (x^2 - 2x + 1)
b - x^2 + 2x - 1
-x^2 + 2x + (b - 1)
We know that c(ax^2 + bx + c) = 24
So b - 1 = 24 ; b 25.
25 - (x - 1)^2
Opening this, we get 24 + 2x - x^2. so a = 2.
How you do this? :/Never mind I got it
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