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Mathematics: Post your doubts here!

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let p's time = t
then q's time = t - 2
a = 1.75 and u = 0 for both
Displacement of P = 0.875t^2
Displacement of Q = 0.875(t-2)^2
Displacement of P - Displacement of Q = 4.9
0.875t^2 - 0.875(t-2)^2 = 4.9
t = 2.4
but since it's talking about time in terms of Q in the question
t = 2.4 - 2
= 0.4
thnk u :)
 
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Q1 why did we take negaive 0.32 and 0.28 it should be only 0.32 right?
 

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can some one help please.. im really confused on when to take the weight component of an object into consideration because sometimes i use it where im nt supposed to and sometimes i dont use where im supposed to use it. For example I didnt know that we need to use it in s14 p43 Q2 (what i mean by the weight component is the gravity force exerted on the mass of the object at an inclined plane which is usually calculated by mgSin(Theta) )
 
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can some one help please.. im really confused on when to take the weight component of an object into consideration because sometimes i use it where im nt supposed to and sometimes i dont use where im supposed to use it. For example I didnt know that we need to use it in s14 p43 Q2 (what i mean by the weight component is the gravity force exerted on the mass of the object at an inclined plane which is usually calculated by mgSin(Theta) )
:confused:
 
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can some one help please.. im really confused on when to take the weight component of an object into consideration because sometimes i use it where im nt supposed to and sometimes i dont use where im supposed to use it. For example I didnt know that we need to use it in s14 p43 Q2 (what i mean by the weight component is the gravity force exerted on the mass of the object at an inclined plane which is usually calculated by mgSin(Theta) )
Always use it when you are using newton's second law ( Fnet = ma)

View attachment 53489 Q3 explanation please?
i)V = P/F
If P increases, V increases, so Vb = 1.2* 28
If F decreases then V increases, so Vb = (1.2 * 28)/0.96 (multiplying by 0.96 will decrease V, so it's divided)

ii)Work done by Driving force + Loss = Work done by resistive force + gain
WD + 0 = (2.3 * 10^6) + (.5)(200000)(35^2-28^2)
 
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doubt.jpg
Always use it when you are using newton's second law ( Fnet = ma)


i)V = P/F
If P increases, V increases, so Vb = 1.2* 28
If F decreases then V increases, so Vb = (1.2 * 28)/0.96 (multiplying by 0.96 will decrease V, so it's divided)

ii)Work done by Driving force + Loss = Work done by resistive force + gain
WD + 0 = (2.3 * 10^6) + (.5)(200000)(35^2-28^2)
thank you bhai :)
can some one help please.. im really confused on when to take the weight component of an object into consideration because sometimes i use it where im nt supposed to and sometimes i dont use where im supposed to use it. For example I didnt know that we need to use it in s14 p43 Q2 (what i mean by the weight component is the gravity force exerted on the mass of the object at an inclined plane which is usually calculated by mgSin(Theta) )
doubt.jpg
 
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P4 MJ 06 Q5 (i) .... I SERIOUSLY DON'T GET IT! -freaking out-
Tension on both sides of the pulley is same, so the right angle can be split into 2 45 degree angles. If you resolve one of these, it's Tcos45.
Since there are 2 of these, the resultant is equal to 2Tcos45
2Tcos45 =4sqrt2
 
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How do we calculate V for the first part?
Ive uploaded mark scheme as well

i saw the mark scheme but it was pretty confusing can anyone please tell me how to form an equation as well?
 

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