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Maths, Addmaths and Statistics: Post your doubts here!

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Re: O'level Maths, Addmaths and Statistics help available he

oops sorry... Q 8 (c) i noe wat to do bt i cant simplify it to wat they've given...
 
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Re: O'level Maths, Addmaths and Statistics help available he

^^^ You Stuck at 5 x square - 22.5 x -5??? or not arrived at it yet? After that you have to divide it by 2.5... To get what they have shown...
 
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Re: O'level Maths, Addmaths and Statistics help available he

(10/x)+2+(15/x+0.5)=7
therefore equation will be
5x(0.5+x)
=10x+15x+5
solve this and this will simplify to that equation
 
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Re: O'level Maths, Addmaths and Statistics help available he

10/x+15/(x+0.5)+2=7

10/x+15/(x+0.5)=5

15/(x+0.50)=5-10/x

15/(x+0.5)=(5x-10)/x
cross multiply
15x=5x^2 + 2.5x -10x-5

5x^2 +2.5x-10x-15x-5=0

5x^2-22.5x-5=0
take 2.5 common
2.5(2x^2-9x-2)=0
therefore 2x^2-9x-2=0
 
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Re: O'level Maths, Addmaths and Statistics help available he

CaptainDanger said:
^^^ You Stuck at 5 x square - 22.5 x -5??? or not arrived at it yet? After that you have to divide it by 2.5... To get what they have shown...
yeah i was stuck there... jxt cudnt thinkk anythng further
 
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Re: O'level Maths, Addmaths and Statistics help available he

i need help in Question 5 part b of this paper

The answer is:
 
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Re: O'level Maths, Addmaths and Statistics help available he

b. i- Numbers are added to get the next value...
a=5+8=13
b=8+13=21

ii- x+y=z

I hope you read it before going for paper... :)
 
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Re: O'level Maths, Addmaths and Statistics help available he

In the diagram, AP = 6 cm and AQ = 8 cm. The radius is 10cm. How do we find the area of the shaded region?
 
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Re: O'level Maths, Addmaths and Statistics help available he

I also need help with Q8 of this paper... specifically the part where it says n(universal set) = 6 × n(C′ ∩ D′). I don't get that..
 
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Re: O'level Maths, Addmaths and Statistics help available he

Are AP and AQ the arcs or the straight lines?
 
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Re: O'level Maths, Addmaths and Statistics help available he

Q8 of the paper you have given is not as tricky as it seems. The marking scheme explains it all.
n(C' ∩ D') are the number of homes that neither have a dishwasher, nor a computer. That is the place empty in the rectangle and not occupied by any of the circles. If you arrange the equation n(universal set) = 6 × n(C′ ∩ D′) as (1/6)n(universal set)=n(C′ ∩ D′), the confusion is removed. Now you know that n(C′ ∩ D′) is 1/6 of the universal set, hence, the 10k you found before is 5/6. You may solve the rest of the question like the ms says.

Hope this helped. :)
 
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Re: O'level Maths, Addmaths and Statistics help available he

Thanks for the explanation for that Q, I got it. :)

Also, in the previous one AP and AQ are straight lines and PQ is an arc.
 
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Re: O'level Maths, Addmaths and Statistics help available he

For that question, draw a line from the P and Q to the center of the diameter and label it O. AO=10cm=PO=QO. First take out angle AOQ and AOP by simple cosine rule and change it into radians.
Now you need to find 5 different areas in order to find the area of the shaded region. Use the formula 0.5absinC for the area of the triangles APO and AQO or use simple triangle area formula. Then find the area of sector AOP and AOQ by the forumula 0.5r­­­²Θ. Now you need to find the area of the unshaded region X enclosed by the line AP and the arc. Do the calculations as following:

Area of X= Area of sector AOP-Area of triangle AOP.
Area of shaded region=Area of sector AOQ-(X+Area of triangle AOQ)

If you require more elaboration on the question tell me. I'll do it using the values and represent the areas on the picture.

Hope this helped. :)
 
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Re: O'level Maths, Addmaths and Statistics help available he

Actually there is a misprinting in 11a. It is tan2x-3cot2x=0. Now I think you can solve it :)
 
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Re: O'level Maths, Addmaths and Statistics help available he

ermmmm okay. and part b??
 
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