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Equation Of AB:xhizors said:sorry but they are C (4, 6)
and my Q's ans are ryt (8.5,0)
Muhammad Talha said:hey plz tell me that how to covert a decimal value into that radian π???
n for paper 1 r u doin the prac of p1 from pst paprs or both p1 n p2?????
tahatehseen said:Equation Of AB:xhizors said:sorry but they are C (4, 6)
and my Q's ans are ryt (8.5,0)
m=(9-10/8+4)=3/4
y=mx+c
Put the values of A
0=3/4(-4)+c
c=3
y=(3/4)x+3
(m of PQ)(m of AB)=-1
m of PQ=-4/3
y=(-4/3)x+c
Substitute values of P
10=-4/3 +c
c=34/3
y=(-4/3)x+34/3
Line AB and PQ intersect at C
Solve the two simultaneous equations..
4y=3x+12
and y=(-4/3)x+34/3
-16x/3 + 136/3 = 3x + 12
-16x+136=9x+36
25x=100
x=4, y=6
Therefore coordinates of C are (4,6)
It was a small mistake in the end!
HOPE THAT HELPED!!
abcde said:24. (a) 3! x 7! = 30, 240.
(b) Possible permutations if the books by Dickens are next to each other = 2! x 8! = 80, 640.
=> Possible permutations if the books by Dickens are separated from one another = 9! - 80, 640 = 282, 240.
(c) I am not getting the same answer as the back of the book here.
Since there are 3 books by Conrad, the possible permutations that they would all be together is = 3! x 7! = 30, 240.
Now 2 books of Conrad can also be next to each other = 2! x 8! = 80,640.
So the possible permutations if Conrad's books are separated = 9! - (80, 640 + 30, 240) = 252, 000.
This is what I think and I may be wrong.
abcde said:I think the answer at the back of the book is wrong. I battled with this question before my exams, too and this is the best I could come up with. I hope some one else can help here. Best of luck!
http://www.xtremepapers.me/CIE/index.ph ... 9_qp_1.pdfCaptainDanger said:xhizors The link you have posted is not working?
xhizors said:http://www.xtremepapers.me/CIE/index.ph ... 9_qp_1.pdfCaptainDanger said:xhizors The link you have posted is not working?
xhizors said:http://www.xtremepapers.me/CIE/index.ph ... 9_qp_1.pdfCaptainDanger said:xhizors The link you have posted is not working?
tahatehseen said:here is ur answer
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