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yea i know CIE walay chayn kay saath paper khatam bhi nai honay deingay (
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yea i know CIE walay chayn kay saath paper khatam bhi nai honay deingay (
True!Don't you think there's too much off-topic here? Please at least regard for others. People might have to go through all of this 'useless' post before posting queries here. Don't be too selfish, chat in off-topic. If you can't refrain then sadly, I'll issue that person a 'warning'.
Yeah it has to touch the x-axis.syed1995 i closed my polygon from the bottom will i lose marks?It touched the x axis i mean... perpendicularly. the midpoint think scale and rest was fine. I m worried
yes from one point it had to touch 0 nd from the other end, it shud be tuching 20Yeah it has to touch the x-axis.
Yes they all are correct . i have understood the c part but i don't understand the way you did b and d part.....(ii) b)
FC =FE + ED + DC
-EF + ED -CD (Opposite sides)
FC=-q +2p -r
c)
AY = 3/4 2p
AY = 3/2p = 1.5p
=FA + AY
-AF +AY
-r +1.5p
AY =1.5p -r
d)
YX=YB + BC + CX
YB - CB + 1/2CD
YX = 0.5p - q + 0.5r
are the answers correct .. If they are I would like to thank you .. because this will be the first time in my life that I have done a vector question correct
there are five numbers so the probability of one number obtained the same three times will be 1/5 x 1/5 x 1/5= 1/125 but since there are five numbers which have the possibility to come so the probability will be 1/125 x 5= 1/25.
Yes they all are correct . i have understood the c part but i don't understand the way you did b and d part.....
there are five numbers so the probability of one number obtained the same three times will be 1/5 x 1/5 x 1/5= 1/125 but since there are five numbers which have the possibility to come so the probability will be 1/125 x 5= 1/25.
to go more simpler, this could be like this:
to go more simpler, this could be like this:
at first picking, we could get any one of the five numbers,right? so probability at stage 1 is 5/5 =1
at second stage, we will have to pick only one number out of 5, to keep it the same as before, so probability is 1/5
at the third stage, we can again pick only one number, so probability is again 1/5
multiplying the three, we get 1* 1/5 * 1/5 = 1/25
that is how we did permutations and combinations in addmaths, right syed1995?
10 (a)http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf
Question 10 part a) and b) please.....
a-i) take the alternate angle of 15 degrees. SBC=90-15= 75http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf
Question 10 part a) and b) please.....
10 (a)
(i)it will be 90-15=75 degrees, coz if u complete the dotted line till u get till SB(mark it as point X), you will se it will be a right angled triangle.
(ii) find SC using cosine formula.
(iii) use sin-1(3oo/SC)
Thanks alot! Help appreciated!a-i) take the alternate angle of 15 degrees. SBC=90-15= 75
ii) Apply cosine rule.
iii) Find BCS and subtract 15 from it.
b-i) CBD=15 (alternate angle). BCD= 180-(90+15)=75. Now apply Sine Rule.http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf
Question 10 part a) and b) please.....
http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf
Question 10 part a) and b) please.....
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