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the way x² multiplied by x gives x³, the power of same base add when we multiply. so x^a into x^b will give x^(a+b)
not rumor it's true, we are dead -_- why did this change had to happen when im sitting for that session
the intersected one must be reduced from the individual one, so the common one is given 4 people, so subtract it from both the event : for morning - 26-4 = 22 , for bbq 29-4 = 25 , that is the number of people who went only to morning cruise n evening bbq, this doesn not include the people who went to both, so adding all the people that is the number of people who went to morning one, bbq one, both , or neither, and they must equal to 50 , as it have said 50 ppl went on tour , so ( 22 + 25 + 4 + 1 = 52? wth , where did these two ppl come from?
so yeah thats why its not possible, to summarize : it must the equal the number of elements according to the given conditions/situation.the intersected one must be reduced from the individual one, so the common one is given 4 people, so subtract it from both the event : for morning - 26-4 = 22 , for bbq 29-4 = 25 , that is the number of people who went only to morning cruise n evening bbq, this doesn not include the people who went to both, so adding all the people that is the number of people who went to morning one, bbq one, both , or neither, and they must equal to 50 , as it have said 50 ppl went on tour , so ( 22 + 25 + 4 + 1 = 52? wth , where did these two ppl come from?
and the least one is 4, and greatest 26, although unsure, correct me if i;m wrong..
somebody please solve this question for me, although this shoulv'e been a easy question but i find it so hard
pleasssee explaain! especially the one with with trapezium thing,, i never did this type of maths..
im sitting for cambridge o level m/j , this is igcse question
Ok wait which chapter is this from? As far as i knw we had to square the given ratios to get the area ratios.or is that jjust for similiar figures :s . And yes the most confusing one is the trapezium one,explain that ,and please mention the chapter's name. :s.. actuallyt xplain the first all diagrams, and the last two of the 2nd diagram
To be honest im still kinda confused with findin greatest and least number of dsomethin related with sets, so anyway this is how i did, when finding greatest or least we usually ignore the leftout element in this case that 1 person who did not attend any event, so we need to draw 2 diag to find least and greatest. First one just the usual one 2 circle and in. Da overlapping part writte 4, the next diagram should be that subset type of circle. So one big n snall circle. So accordin to da given info we had 26 mornin n 29 bbq , so we put 26 in the small circle it being the subset of the bigger circle, and put the number 3 in the big one, adding up wud make it 29! That is the greatest number of ppl goin to both events,and the least 4.hope u got it.Thanks I got the first part
but I don't seem to understand how you calculated the least and greatest?
and thanks once again
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