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Maths, Addmaths and Statistics: Post your doubts here!

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The examiner report says: This part was often omitted. Only a few correct answers were seen with many candidates giving a = 1 as their solution
 
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3(i) the magnitude of a unit vector is always 1.
0.28^2+p^2=1
p=0.96
(ii) 12i+17j-qi+7j=k0.28i+k0.96j
(12-q)i+24j=k0.28i+k0.96j
k=25
12-q=25*0.28
q=-8


hoped this helped!

tell me how u did second part. i never knew that magnitude of a unit vector is 1 :p
 
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if R = rs 500 n = 10 and i = 6% then amount of ordinary anuuity

A RS 4580.11
B RS 8131.22
C RS 6590.42
D RS 5862.42

for ordinary annuity

-n
P = R[1-(1+i) ]
divide
i

plzz some help me how to find it as m not able too :(
 
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If A =
[1 1 ]
[0 1] THEN ITS INVERSE IS

A [1 -1]
[0 1 ]

B [-1 -1]
[0 -1]

C [1 0]
[0 1 ]

D
[0 1]
[1 1]
 
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if R = rs 500 n = 10 and i = 6% then amount of ordinary anuuity

A RS 4580.11
B RS 8131.22
C RS 6590.42
D RS 5862.42

for ordinary annuity

-n
P = R[1-(1+i) ]
divide
i

plzz some help me how to find it as m not able too :(

Ordinary Annuity = R{[(1+i)^n]-1}/i

So answer is 500 x [(1.06^10)-1]/0.06 = 6590
 
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