- Messages
- 313
- Reaction score
- 50
- Points
- 38
Also i dont get what u say in the last part of your question![]()
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Also i dont get what u say in the last part of your question![]()
i did the same but the time equals to 0 in the end i'll do it once more. anyways thanksFor the last part u have to use t as the time where both of the objects meet at one point so u have to do this first find the position vector at time t by first multiplying t to velocity vector and then add it to the original position vector now equate both equations together as at t the position vector of both are same now u get t !
After finding t insert t into any of the position vectors at time t and here u have the position vector at the point of intersection !
i was asking that how can we find velocity? i mean the speed is already given and i'm confused how they got the velocity by the method done in mark scheme.
![]()
Scouser,Can you please make a diagram and show it to me?I got 45 km/h but just cant seen to make the diagram.Isnt the formula VL/s = VL- Vs ?KTBFFH.
now i understand !See the triangle in the figure and see if u get it !
i agree! i have many problems in add maths and no teacher to help me!I think we should have a seperate thread for O Levels Add maths .. because i am pretty sure O level maths students are pissed at us for discussing something which kinda goes over their heads
what do you add maths students say ?![]()
i can't get the bearing! i have found the angle between the velocity of ship and lifeboat using the sine rule it comes to 79 and then i minus 30 from it to get the bearing. but the answer is wrong!First find the relative velocity im pretty sure u guys know that
use the equation
V(L/S) = V(L) + (-V(S))
then use a scale of possibly 1 cm = 5km/h and plot a relative velocity line at a bearing of 270* which should if i remember it correctly about 9 cm then make an arrow showing that its moving towards the left !
Now connect the -V(s) line towards the left end of the relative velocity line u made before in such a way that u make 150* so the angle between the relative line and this new line is 60* now this line should be of 3 cm !
Last just join the remaining line to the figure and u got the diagram now use cosine rule for first part then sine rule and a bit of bearing knowledge in second part that all![]()
i dont!who doesnt![]()
see if this image helps :
tell me if this helps:http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_s11_qp_21.pdf i can't find the correct second value of z in question 10 part iii it's about trigonometry
http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_s09_qp_2.pdf and the question 11 b part
please![]()
4 Six-digit numbers are to be formed using the digits 3, 4, 5, 6, 7 and 9. Each digit may only be
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now