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Maths, Addmaths and Statistics: Post your doubts here!

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For the last part u have to use t as the time where both of the objects meet at one point so u have to do this first find the position vector at time t by first multiplying t to velocity vector and then add it to the original position vector now equate both equations together as at t the position vector of both are same now u get t !
After finding t insert t into any of the position vectors at time t and here u have the position vector at the point of intersection !
i did the same but the time equals to 0 in the end i'll do it once more. anyways thanks :)
 
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Scouser,Can you please make a diagram and show it to me?I got 45 km/h but just cant seen to make the diagram.Isnt the formula VL/s = VL- Vs ? :) KTBFFH.
 
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I think we should have a seperate thread for O Levels Add maths .. because i am pretty sure O level maths students are pissed at us for discussing something which kinda goes over their heads :D

what do you add maths students say ? :p
 
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Scouser,Can you please make a diagram and show it to me?I got 45 km/h but just cant seen to make the diagram.Isnt the formula VL/s = VL- Vs ? :) KTBFFH.

Make sure u connect the - Velocity of s and not + !
And connect the Velocity of S at the destination !
If u still dont get it ill make a random sketch and show u !
 
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I think we should have a seperate thread for O Levels Add maths .. because i am pretty sure O level maths students are pissed at us for discussing something which kinda goes over their heads :D

what do you add maths students say ? :p
i agree! i have many problems in add maths and no teacher to help me!
 
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First find the relative velocity im pretty sure u guys know that :D
use the equation
V(L/S) = V(L) + (-V(S))
then use a scale of possibly 1 cm = 5km/h and plot a relative velocity line at a bearing of 270* which should if i remember it correctly about 9 cm then make an arrow showing that its moving towards the left !
Now connect the -V(s) line towards the left end of the relative velocity line u made before in such a way that u make 150* so the angle between the relative line and this new line is 60* now this line should be of 3 cm !
Last just join the remaining line to the figure and u got the diagram now use cosine rule for first part then sine rule and a bit of bearing knowledge in second part that all :D
i can't get the bearing! i have found the angle between the velocity of ship and lifeboat using the sine rule it comes to 79 and then i minus 30 from it to get the bearing. but the answer is wrong!:(!!
 
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If your query is answered, ignore this, as i am a bit late




for 4 digit number greater than 3000, the first number can be any one from 3,4,5,6 so 4C1
for the next three digits out of 5 the arrangement can be as follows : 5P3
so answer is 4C1 * 5P3 = 240

see if this image helps :
admaths 1.JPG

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_s11_qp_21.pdf i can't find the correct second value of z in question 10 part iii it's about trigonometry
tell me if this helps:

Scanner Pics 005.jpg
Scanner Pics 006.jpg
 
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4 Six-digit numbers are to be formed using the digits 3, 4, 5, 6, 7 and 9. Each digit may only be
used once in any number.
(iv) even and greater than 500 000. [3]
.
for greater than 500 000, the condition would be that the first digit contains 5,6,7,9
for even, the condition would be that the last digit contains 4,6
.
the problem here is that if we take four as last digit, we will have choice of 4 numbers for first digit, but if we take 6 as last digit, only three numbers could be chosen from for first digit. the numbers in between are arranged as 4! .
so the two conditions would be:
4C1 * 4! * 1 = 96 IN CASE OF FOUR
3C1 * 4! * 1 = 72 IN CASE OF SIX
THE RESULT WOULD BE 96 + 72 =168
 
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Can you just make a diagram using velocities? Distance and velocity on the same diagram is confusing. -_-
 
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