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Also i dont get what u say in the last part of your question![]()
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Also i dont get what u say in the last part of your question![]()
i did the same but the time equals to 0 in the end i'll do it once more. anyways thanksFor the last part u have to use t as the time where both of the objects meet at one point so u have to do this first find the position vector at time t by first multiplying t to velocity vector and then add it to the original position vector now equate both equations together as at t the position vector of both are same now u get t !
After finding t insert t into any of the position vectors at time t and here u have the position vector at the point of intersection !
i was asking that how can we find velocity? i mean the speed is already given and i'm confused how they got the velocity by the method done in mark scheme.
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Scouser,Can you please make a diagram and show it to me?I got 45 km/h but just cant seen to make the diagram.Isnt the formula VL/s = VL- Vs ?KTBFFH.
now i understand !See the triangle in the figure and see if u get it !
i agree! i have many problems in add maths and no teacher to help me!I think we should have a seperate thread for O Levels Add maths .. because i am pretty sure O level maths students are pissed at us for discussing something which kinda goes over their heads
what do you add maths students say ?![]()
i can't get the bearing! i have found the angle between the velocity of ship and lifeboat using the sine rule it comes to 79 and then i minus 30 from it to get the bearing. but the answer is wrong!First find the relative velocity im pretty sure u guys know that
use the equation
V(L/S) = V(L) + (-V(S))
then use a scale of possibly 1 cm = 5km/h and plot a relative velocity line at a bearing of 270* which should if i remember it correctly about 9 cm then make an arrow showing that its moving towards the left !
Now connect the -V(s) line towards the left end of the relative velocity line u made before in such a way that u make 150* so the angle between the relative line and this new line is 60* now this line should be of 3 cm !
Last just join the remaining line to the figure and u got the diagram now use cosine rule for first part then sine rule and a bit of bearing knowledge in second part that all![]()
i dont!who doesnt![]()
see if this image helps :
tell me if this helps:http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_s11_qp_21.pdf i can't find the correct second value of z in question 10 part iii it's about trigonometry

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_s09_qp_2.pdf and the question 11 b part
please![]()

4 Six-digit numbers are to be formed using the digits 3, 4, 5, 6, 7 and 9. Each digit may only be
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