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Maths, Addmaths and Statistics: Post your doubts here!

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Eight people go to a theatre and sit in a particular group of eight adjacent seats. Three of the eight belong to one family and sit together. If the other five don't mind where they sit, except that the 2 of them refuse to sit together, find the number of possible seating arrangements for all eight people.

ANSWER NEEDED FAST.
2 x 5p3....thats my guess...i am probably wrong..:D
you have the answer??
 
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4.Probability Question if anyone has Classified Mathematics it is Question 4 from topic 9
A ball is dropped at random into one of the eight holes, numbered as shown in the diagram. The number under each hole gives the score obtained when the ball drops into a hole.
(there are four holes numbered 1, three holes numbered 2 and one hole numbered 3)
and the probability of scoring 1 is 4/8 and so on.

b) If the ball is dropped twice,find the probability of scoring a total of 4
(4/8 * 1/8) + (3/8 * 3/8) = 13/64
 
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4.Probability Question if anyone has Classified Mathematics it is Question 4 from topic 9
A ball is dropped at random into one of the eight holes, numbered as shown in the diagram. The number under each hole gives the score obtained when the ball drops into a hole.
(there are four holes numbered 1, three holes numbered 2 and one hole numbered 3)
and the probability of scoring 1 is 4/8 and so on.

b) If the ball is dropped twice,find the probability of scoring a total of 4
I got the answer 13/64 but the answer at the back of the book is 17/64
:/

1+3 and 2+2 and 3+1

(4/8 * 1/8) + (3/8 * 3/8) + (1/8 * 4/8 ) = 17/64
 

asd

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2 x 5p3....thats my guess...i am probably wrong..:D
you have the answer??
Yes, i got it. The 2 who do not want to sit together are made to, and then the answer is subtracted from the total number of possibilities.
Possibilities in which they sit together =3!(for the three in a family)*2!(for the 2 who do not want to sit together) *5!(for the remaining 3 and 2 blocks) = 1440
Total no. of possibilities = 3!*6!=4320
therefore, 4320 - 1440 = 2880.
 

asd

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And also, from the digits 3,4,5,6,7, and 9, find the ways in which a six digit number can be made if the number has to be even, and more than 500,000.
digits should not be repeated.
 
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And also, from the digits 3,4,5,6,7, and 9, find the ways in which a six digit number can be made if the number has to be even, and more than 500,000.
digits should not be repeated.

higer than 500,000
btw is there a 8 there or not??
 
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And also, from the digits 3,4,5,6,7, and 9, find the ways in which a six digit number can be made if the number has to be even, and more than 500,000.
digits should not be repeated.
3! x 4! = 144
am i right...what's the answer ???
 
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