Maths, Addmaths and Statistics: Post your doubts here!

[Ikram Khaliq]

ADD-MATHS. 4037/12/O/N/11 question no. 8. i wager the marking scheme is wrong on this one.

 

[Ikram Khaliq]

need help with this

 

[thughamza]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_w11_qp_11.pdf
in Q No 6 part b, i don't understand exactly how to find the value of a and c with proper working
and also Q n0 7 second part.

In Q7 part 2 you have to break up the combation say Nc1=(N)N-1/2! and so on.and you have to calculate a term in which we cut out x.

 

[ashiqbal]

ADD-MATHS. 4037/12/O/N/11 question no. 8. i wager the marking scheme is wrong on this one.

bro please try to post link with query!

 

[Shahryar1]

Can anyone please send me the marking scheme of May/June 2002 Add Maths paper 1?

 

[ashiqbal]

Can anyone please send me the marking scheme of May/June 2002 Add Maths paper 1?

no sorry yar! post a question, i will solve your query or give answer!

 

[Translucent231]

Ikram Khaliq

haha i posted this earlier, The mark scheme is wrong 100% gurranteed, if u use their equation u will get the wrong answer and the funny part is.. the examiner report has a different answer but the one in Examiner report is correct 4y + 3x = 2 is the correct equation y − 4 = 3( x − 2) is the wrong one.

 

[asaadfazal]

help needed in http://www.xtremepapers.com/papers/...matics - Additional (4037)/4037_w11_qp_23.pdf question 6 part 2

I am getting 4 values where as the marking scheme says 2 and the calculation is also taking more space then given so can any one please post a correct solution to the problem.

 

[ashiqbal]

help needed in http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_w11_qp_23.pdf question 6 part 2

I am getting 4 values where as the marking scheme says 2 and the calculation is also taking more space then given so can any one please post a correct solution to the problem.

x can never be negative here!!! you see this is because when we take out of modulus, it will be positive always! multiplying x by 2 must therefore to be +ve, so x must be +ve

 

[thughamza]

http://www.xtremepapers.com/papers/...matics - Additional (4037)/4037_w11_ms_13.pdf Q12 Please :O

 

[Shahryar1]

no sorry yar! post a question, i will solve your query or give answer!

Nah thanks man. I just needed to check for any mistakes. Thanks anyways

 

[Ikram Khaliq]

Ikram Khaliq

haha i posted this earlier, The mark scheme is wrong 100% gurranteed, if u use their equation u will get the wrong answer and the funny part is.. the examiner report has a different answer but the one in Examiner report is correct 4y + 3x = 2 is the correct equation y − 4 = 3( x − 2) is the wrong one.

thank you. btw has the e.r. come out yet?

 

[ashiqbal]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_w11_ms_13.pdf Q12 Please :O

post the link for the question paper!
Anyway, please be a bit specific about which part? Q 12 EITHER, OR, part (i) (ii) (iii) (iv) or (v)? or which of these do you not understand?

 

[thughamza]

Either part i , v and or Part i

 

[HarisLatif]

http://www.xtremepapers.com/papers/...matics - Additional (4037)/4037_w11_qp_23.pdf
I need help in the 12 Question OR part (i) and EITHER part (iii)

 

[HarisLatif]

x can never be negative here!!! you see this is because when we take out of modulus, it will be positive always! multiplying x by 2 must therefore to be +ve, so x must be +ve

in second part of this question i'm getting only one value because the graph of y=2x cuts that graph drawn in first part only at one place. can you please draw that graph? i don't know if mine is correct or not and the marking scheme doesn't provide enough information for the turning points and x,y intercepts....

 

[ashiqbal]

in second part of this question i'm getting only one value because the graph of y=2x cuts that graph drawn in first part only at one place. can you please draw that graph? i don't know if mine is correct or not and the marking scheme doesn't provide enough information for the turning points and x,y intercepts....

have u reflected the graph? i mean the part that is below x axis to above x axis? try doing that!

 

[HarisLatif]

have u reflected the graph? i mean the part that is below x axis to above x axis? try doing that!

i have reflected it and both graphs are cutting at only one place...

 

[asaadfazal]

x can never be negative here!!! you see this is because when we take out of modulus, it will be positive always! multiplying x by 2 must therefore to be +ve, so x must be +ve

thanks for the help really appreciated!!!!

 

[asaadfazal]

in question#8 of http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_w11_qp_12.pdf i am getting midpoint (2,-1), gradient of AB=4/3, gradient of CD=-3/4 and the equation is turning out to be 4y+3x=2 but the marking scheme (http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics - Additional (4037)/4037_w11_ms_12.pdf) says other wise and i am getting 2 answers for both part 2 and 3 which are both included in the marking scheme. So can some one please post a correct solution or tell what am i doing wrong here or is there a miss print some where which i think would hardly be the case.