Maths, Addmaths and Statistics: Post your doubts here!

[ashiqbal]

how do we integrate separately?

you can do it like this /(x4cos4x + sin4x) = /(x4cos4x) + /(sin4x)

 

[asd]

Guys any REAL DIFFICULT paper you've come across, DO tell me plZ!

 

[ashiqbal]

Guys any REAL DIFFICULT paper you've come across, DO tell me plZ!

try s05_qp2 Q 8 and 9 and 11

 

[asd]

try s05_qp2 Q 8 and 9 and 11

could you do these yourself?
And ok, ill see them.

 

[ashiqbal]

could you do these yourself?
And ok, ill see them.

already did! you want me to show it here?

 

[asd]

Nah, just wanted to know whether you knew how to solve these.
And oh relative velocity, it's interesting.
ashiqbal

 

[ashiqbal]

Nah, just wanted to know whether you knew how to solve these.
And oh relative velocity, it's interesting.
ashiqbal

yup!

 

[asd]

yup!

you got more relative velocity questions?

 

[HarisLatif]

yup!

please solve this one.
how many different odd4 digit numbers less than 4000 can be formed from the digits 1,2,3,4,5,6,7 if no digit may be repeated. please hurry

 

[Haris Bin Zahid]

HarisLatif or syed1995 or multixamza01, I need help here in this question (only the first part):
Given that y=kx^2 -4x +3k, express y in the form a(x-p)^2+q, where a, p and q are in terms of k. Hence find the value of k if the maximum value of y is 4.

 

[asd]

please solve this one.
how many different odd4 digit numbers less than 4000 can be formed from the digits 1,2,3,4,5,6,7 if no digit may be repeated. please hurry

2*6*5*4 = 240
is this the answer?

 

[HarisLatif]

2*6*5*4 = 240
is this the answer?

the answer is 200. (

 

[Haris Bin Zahid]

the answer is 200. (

Plz man, help in the question above

 

[asd]

the answer is 200. (

year?

 

[ashiqbal]

please solve this one.
how many different odd4 digit numbers less than 4000 can be formed from the digits 1,2,3,4,5,6,7 if no digit may be repeated. please hurry

is answer 20?
like this
if first digit is 1 or 3, then 2C1 * 3C1 * 2! = 12
if first digit is 2, then 1C1 * 4C1 * 2! = 8
12 + 8 = 20

please tell me if i am correct!

 

[asd]

is answer 20?
like this
if first digit is 1 or 3, then 2C1 * 3C1 * 2! = 12
if first digit is 2, then 1C1 * 4C1 * 2! = 8
12 + 8 = 20

please tell me if i am correct!

its 200

 

[asd]

is answer 20?
like this
if first digit is 1 or 3, then 2C1 * 3C1 * 2! = 12
if first digit is 2, then 1C1 * 4C1 * 2! = 8
12 + 8 = 20

please tell me if i am correct!

We will do permutations oye

 

[HarisLatif]

HarisLatif or syed1995 or multixamza01, I need help here in this question (only the first part):
Given that y=kx^2 -4x +3k, express y in the form a(x-p)^2+q, where a, p and q are in terms of k. Hence find the value of k if the maximum value of y is 4.

after the completing square method,i'm getting this: k(x-2/k)^2+3k^2-4/k. so a=k ,p = 2/k and q= 3k^2-4/k. correct?

 

[Sarah22]

http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_w08_qp_2.pdf
(9)(b)(ii)
http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_s09_qp_2.pdf
(5)(a)(i)(c),(a)(ii), (7)(b)(iii), (8)(a)(ii), (11)(b)(iii)(b).
Thank u in advance.. with method please..

 

[HarisLatif]

i tr

its 200

its 200

i tried the same method as ashiqbal did