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Maths, Addmaths and Statistics: Post your doubts here!

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http://clickpapers.net/past papers/math-/4024_s10_qp_12.pdf q.9 part c ??? anyone pls help ?? need to understand it :eek:

Dost is sawal mein phele to tumhe ye pata hona chahiye k agr tum kissi ka under root nikal te ho to us ke pairs honay chahiye under root mein like
if (squareROot4) then we can write (squareRoot 2 x 2) yaha 2 ka ek pair hai to wo root k bahar ajeaga thus Squareroot of 4 will be
just like (SquareRoot8) is mein hum likh saktay hai (SquareRoot 2 x 2 x 2) to ye hojae ga (2SquareRoot2) q k yaha ek pair tha to ek 2 bahar agaya aur unpaired 2 ander he reh gaya now returnig to question

168 = 2^3 x 3 x 7
is ko agr perfect square banana hai to har kisi kay complete pair honay chahiyay, thus 2 ka pair kar nay liya 2 se multiply karegay 3 ka pair complete karnay k liye 3 se multiply karegay and so for 7
thus n = 2 x 7 x 3 = 42
 
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C an anyone post like very difficult questions on indices... its a pretty simple topic but i want proper practice
 
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7 b (iii) u calculated area of triangle AOB
like 0.5 x 9 x 9 x sin 140 = 26.03 cm2
height of triangle will be 0.5AB/tan 70
then area of triangle will be 0.5 x b x h
0.5 x 0.5AB/tan70 x AB = 26.03
AB = 16.9cm (tell me if its correct)

The others are correct, but this answer is not correct..
 
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tariqa yahe hai, tum phir se sukoon se try karna mein ne direct yaha solve kia to isliye mistake kar gaya hoon :)
 
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