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Maths, Addmaths and Statistics: Post your doubts here!

asd

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Sir arsalan...
I guess they will only give marks on the mid values and the lines joined through these points on the graph. Not on joining the lines to the x-axis or not, because i've seen both, some do join some don't. Though I did join them to x-axis (because in D3 they have joined them)
 
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I guess they will only give marks on the mid values and the lines joined through these points on the graph. Not on joining the lines to the x-axis or not, because i've seen both, some do join some don't. Though I did join them to x-axis (because in D3 they have joined them)
yeah I also found both..
 
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Don't you think there's too much off-topic here? Please at least regard for others. People might have to go through all of this 'useless' post before posting queries here. Don't be too selfish, chat in off-topic. If you can't refrain then sadly, I'll issue that person a 'warning'.
 
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Don't you think there's too much off-topic here? Please at least regard for others. People might have to go through all of this 'useless' post before posting queries here. Don't be too selfish, chat in off-topic. If you can't refrain then sadly, I'll issue that person a 'warning'.
Its about time you came. It was getting a bit frustrating!
 
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I had a different approach.

(n-2) * 180
(5-2) * 180
3 * 180 = 540

4x + 4x + 2x + 80 + 80 = 540
10x + 160 = 540
10x = 380
x=380/10

x = 38
 
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fellas i went throgh the marking scheme of previous year containg frequency polygon...
there one mark was for plotting values against mid points and other mark was for joining with straight lines at appropriate heights..
no mention was done for extending lines to x axis :)
 
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Don't you think there's too much off-topic here? Please at least regard for others. People might have to go through all of this 'useless' post before posting queries here. Don't be too selfish, chat in off-topic. If you can't refrain then sadly, I'll issue that person a 'warning'.
Hmm i deltd some of my previous useless post (y)
 
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I had a different approach.

(n-2) * 180
(5-2) * 180
3 * 180 = 540

4x + 4x + 2x + 80 + 80 = 540
10x + 160 = 540
10x = 380
x=380/10

x = 38

its not a diffrent appraoch you to have same method and same appraoch just you considered a whole figure while I considered half of it due to line of symmetry !!;)
 
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and Q10 biii. take the perimetre of both rectangle and square, add them and equate it to 28 which is the total length of the wire. if you put x=1.88 then the perimetre will be less than 28 while if you put x=26.1 it will exceed 28 that's why it is not possible to have x=26.1 as width of rectangle.
 
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