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Maths, Addmaths and Statistics: Post your doubts here!

Suchal Riaz

Suchal Riaz

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mohdumar said:
well if u have time it can help everyone!!! btw my teacher has really taught this chapter well
Click to expand...
nobody is interested in it. nobody gave me asnwer that they want to see them. so i guess i should not waste my time. but if anyone would say me to make notes on any topic, i will inshallah make them.
 
Z

Zohaib_Zed

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tell me the solution of this question....
Two telephone companies have different ways of charging their customers.
(i) Michael uses Company A which charges 6 cents for each unit or part unit of time.
A unit of time is 200 seconds.
He makes a call lasting 1 hour 22 minutes.
Calculate the cost of his call. [2]
(ii) Norman uses Company B which charges 5 cents for each of the first 400 units.
The charge for each additional unit is reduced by one quarter.
There is also a fixed charge of $27 for the use of the equipment.
He is charged for 629 units.
Calculate, correct to the nearest cent, the total sum that he has to pay
 
Unique@work

Unique@work

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plz hlp me...................
i am lft wit only 3 months n i hav to do D1,D2,D3,D4 nd addendum
tel me hw to secure A* in maths
plz repli soon as m out ov tym......................:confused::cry:
 
Suchal Riaz

Suchal Riaz

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Unique@work said:
plz hlp me...................
i am lft wit only 3 months n i hav to do D1,D2,D3,D4 nd addendum
tel me hw to secure A* in maths
plz repli soon as m out ov tym......................:confused::cry:
Click to expand...
do past papers. if you feel some problem, then read the explanation of that topic and then move directly to past papers. If you have a teacher to explain you the topic then you don't need book at all. if u have problem in graphs my graphs notes might be helpful. see the link in my signature.
 
Suchal Riaz

Suchal Riaz

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kainat husain said:
MATHS HELP NEEDED
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s03_qp_4.pdf
q- 6 how to do that simplification like m gettin sum other answer! pls show in a detailed way how to simplify! i want to know how to do the whole question 6!!!!
please help its urgentttt!!!!!
Click to expand...
(a)(i): volume of cuboid is length*breadth*hight. so simply write: (2x)(x+4)(x+1) cm³
(a)(ii): expand it and then simplify. see attachment for detailed processs.
(b)(i): it says that the width is 1cm so inner area will be reduced from each side by 1cm, so 2cm for each dimension.
(b)(ii): to fing volume of wood subtract volume of all of the box by volume of inside of the box. volume of inside is found by multiplying the internal dimesions.
1-it is 2x³+2x²-4x. when we substract total volume from it we get volume of wood.
2-(2x³+10x²+8x)-(2x³+2x²-4x)=8x²+12x
(c)(i)
as the area of wood we found in previous question is 8x²+12x and the questions tells us that real value is 1980cm³, so 8x²+12x must be equal to 1980cm³.
so put them equal to each other:
1- 8x²+12x=1980
2- 4(2x²+3x)=1980
3- 2x²+3x=1980/4
4- 2x²+3x=495(substract both sides by 495)
5- 2x²+3x-495=0

(c)(i): solve quadrativ by this formula; [-b±√(b²-4(a*c))]÷2(a)(see attachment)
(c)(ii): in each dimension put positive value of x as length can not be negative. the answers are 30 cm *19 cm  * 16 cm.


(a)(ii)(a)(ii).png(c)(i) (c)(i).png
 

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  • (a)(ii).png
    (a)(ii).png
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kainat husain

kainat husain

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Suchal Riaz said:
(a)(i): volume of cuboid is length*breadth*hight. so simply write: (2x)(x+4)(x+1) cm³
(a)(ii): expand it and then simplify. see attachment for detailed processs.
(b)(i): it says that the width is 1cm so inner area will be reduced from each side by 1cm, so 2cm for each dimension.
(b)(ii): to fing volume of wood subtract volume of all of the box by volume of inside of the box. volume of inside is found by multiplying the internal dimesions.
1-it is 2x³+2x²-4x. when we substract total volume from it we get volume of wood.
2-(2x³+10x²+8x)-(2x³+2x²-4x)=8x²+12x
(c)(i)
as the area of wood we found in previous question is 8x²+12x and the questions tells us that real value is 1980cm³, so 8x²+12x must be equal to 1980cm³.
so put them equal to each other:
1- 8x²+12x=1980
2- 4(2x²+3x)=1980
3- 2x²+3x=1980/4
4- 2x²+3x=495(substract both sides by 495)
5- 2x²+3x-495=0

(c)(i): solve quadrativ by this formula; [-b±√(b²-4(a*c))]÷2(a)(see attachment)
(c)(ii): in each dimension put positive value of x as length can not be negative. the answers are 30 cm *19 cm  * 16 cm.


(a)(ii)View attachment 21008(c)(i) View attachment 21009
Click to expand...
thnxxxx a lot :D
 
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