Maths, Addmaths and Statistics: Post your doubts here!

[ZohaKhan]

Anywys thnx alot ) It helped alot

 

[***amd***]

Sine30= 0.5.. did u mean dis?

no.

 

[ZohaKhan]

thnx if u can pls help me wid the rest postd questions

 

[***amd***]

http://maxpapers.com/syllabus-materials/mathematics-d-4024/attachment/4024_w13_qp_21/
Q.8A
Q.10A i

Awesome12, remember i this Q10? let me test u
Zoha sis, i'll do this tomorrow In Shaa Allah

 

[ZohaKhan]

Awesome12, remember i this Q10? let me test u
Zoha sis, i'll do this tomorrow In Shaa Allah

Thanks a bunch

 

[Asad.Babur]

How long will it take to solve Add-Maths past papers from 2007 to 2013?

Thus 7 Years, to 7 days, but must do 4 a day

 

[Asad.Babur]

32 papers from 2010 to 2013 november. 12 papers from 2007 to 2009.

Total 44 papers.

44 * 1.5 = 66 hours.

If i solve 2 papers a day, it will be minimum of 22 days.

And i still haven't studied the latest topics of Integration, Relative Velocity, Kinematics. Can't find a good teacher. >.<
Not to mention all the other subjects i have to study, too. And all their past papers.

So Conclusion: It's impossible to get a distinction. Right?

Who the hell tells you to do 2 a day? I can do 6-7 a day worthy 1.5 hours

It is not Impossible

 

[***amd***]

http://maxpapers.com/syllabus-materials/mathematics-d-4024/attachment/4024_w13_qp_21/
Q.8A
Q.10A i

Q8...

use the Pythagoras theorem and you'll get the answer.

Q10...

find the arc length AB (= 90/360 * 2 pie r) and multiply it with the height of the cylinder.

 

[Lilly2318]

kindly help me wid the last 2 parts. explain fully. i knw that x=0

 

[Asad.Babur]

kindly help me wid the last 2 parts. explain fully. i knw that x=0
View attachment 38040

***amd***, Awesome12

Help her, I am, as always, usedlessed

 

[***amd***]

kindly help me wid the last 2 parts. explain fully. i knw that x=0
View attachment 38040

ii)
just put the value of x in the equation,
y = 5a^x
any number^0 = 1(Remember this!)
and thus y = 5a^0 = 5 * 1 = 5
and the coordinates are (0, 5)
iii)
join the 2 points P (0, 5) and (2, 45)
and find gradient
like, m = (y1-y2)/(x1-x2) = (45-5)/(2-0) = 40/2 = 20

 

[Asad.Babur]

ii)
just put the value of x in the equation,
y = 5a^x
any number^0 = 1(Remember this!)
and thus y = 5a^0 = 5 * 1 = 5
and the coordinates are (0, 5)
iii)
join the 2 points P (0, 5) and (2, 45)
and find gradient
like, m = (y1-y2)/(x1-x2) = (45-5)/(2-0) = 40/2 = 20

LOL! I could have done that, HELL ME!

 

[Asad.Babur]

***amd***, cant believe you just liked that

 

[ZohaKhan]

Q8...
View attachment 38038
use the Pythagoras theorem and you'll get the answer.

Q10...
View attachment 38039
find the arc length AB (= 90/360 * 2 pie r) and multiply it with the height of the cylinder.

Aargh m so sorry but pls explain n solv q,10,Bi and ii fully

 

[Asad.Babur]

Aargh m so sorry but pls explain n solv q,10,Bi and ii fully

Zoha Sis,

(i) Formulae here is = Pi*Speed*Square of Radius

So, in this case
Pi =Moslty 3.142, but Varies Calculator to Calculator
Speed = 300cm/s as given
Sqaure of Radius = 4.5 * 4.5 = 20.25

hence we have, 3.142 (Pi) x 300 (Speed) x 20.25 (Sqaure of Radius)= 19087.65cm/s

Lets Simplyfy =19088 cm/s or 19.1 liters
.......................................................................................................................................................

You might want to check Marking Schemes, it is more dependant on value of Pi, like it can vary a little, but you wont lose marks.......
.......................................................................................................................................................

Now,

(ii) in a minute you will have 19.1 x 60 =1416 Liters Sent throught pipe

So for 25000 Liters, we will need 25000/1416= 21.81 Minutes, ... Rounded to 22 minutes

P.S: I am not Professional like amd, so Check the Marking Scheme

***amd***, you might be helpful, if I am incorrect!

 

[ZohaKhan]

hey but Bi's ans is 19100?

 

[***amd***]

Aargh m so sorry but pls explain n solv q,10,Bi and ii fully

Zoha Sis,

(i) Formulae here is = Pi*Speed*Square of Radius

So, in this case
Pi =Moslty 3.142, but Varies Calculator to Calculator
Speed = 300cm/s as given
Sqaure of Radius = 4.5 * 4.5 = 20.25

hence we have, 3.142 (Pi) x 300 (Speed) x 20.25 (Sqaure of Radius)= 19087.65cm/s

Lets Simplyfy =19088 cm/s or 19.1 liters
.......................................................................................................................................................

You might want to check Marking Schemes, it is more dependant on value of Pi, like it can vary a little, but you wont lose marks.......
.......................................................................................................................................................

Now,

(ii) in a minute you will have 19.1 x 60 =1416 Liters Sent throught pipe

So for 25000 Liters, we will need 25000/1416= 21.81 Minutes, ... Rounded to 22 minutes

P.S: I am not Professional like amd, so Check the Marking Scheme

***amd***, you might be helpful, if I am incorrect!

i dunno i just typed the answer

Aargh m so sorry but pls explain n solv q,10,Bi and ii fully

i) just find the area of this shaded cylindrical region
ii) 1 cubic cm = 1 ml
and 25000 l = 25000000 ml

so time taken for 1 ml (cubic cm) to come out = 1 sec
thus time taken for 25000000 ml = 25000000/(Volume u found in 'i')

 

[ZohaKhan]

n wen i m dividing 25000/1416 in Bii ..ans is not 21.81

 

[ZohaKhan]

ididnot get it...*sigh*

 

[Asad.Babur]

n wen i m dividing 25000/1416 in Bii ..ans is not 21.81

n wen i m dividing 25000/1416 in Bii ..ans is not 21.81

Oh , Typed incoreect ......... It 1146, You can do it yoursef (19.1 x 60)