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Hey have you played Assassins Creed 3?I'm installing it now,is it any good?3a -2c 3a -2c 9a - 6c 3(3a - 2c) 3
------------- = ------------- = ------------- = ------------- = ---- = 1.5
4 1 6a - 4c 2 (3a - 2c ) 2
2a - --- c -- (6a - 4c )
3 3
Yah bhee nae atta to Allah khair karey app kee
Aur 2a - 3/4c nae , 2a - 4/3 c haiitna time main ghaltee dhoondta raha
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Alright. Thanks.Ap time 30s ki line kay sath ley rahay ho jabkay hamnay , 60s ya 0 kay sath lena hai.
Tu it should be,
0.2 = x / 20 (Kyunkai x is the velocity at t=40 and it reduces to 0 and 20 is 60-40)
just 4 , that was pretty goodHey have you played Assassins Creed 3?I'm installing it now,is it any good?
After cutting we are left with 3a-2c/ 2a-3/4c.. How do we deduce the answer now?
xpc removed all the spaces
Mje laga ab bhi mje kuch samajh nahi a raha shayd.
what Are you asnwers for that question you posted ?ans my questionnnnnnnnnnn![]()
.-. I'm dumb.12 c I would do it by a longer method but surer
View attachment 43605
Now see
OBA = 0.5 x (3a -2c) x (4a) x sin BAO
OPA = 0.5 x (2a- 4/3 c) x (4a) x sin AOP
when we divide them 0.5, 4a and the sine s get cut
simplify the remaining to get the answer![]()
What's in the other question?.-. I'm dumb.
and what about the other Q?
70 ishhow much marks are you guys getting in P1's?
tht,s wht I have been trying to say tht the HEIGHT component in the line OP and BA wud be such tht it will be dependant on their length as they both subtend the same angle...so the height of theirs wud differ such tht Height of BA wud be 1.5 times(dependant on their length whuch we have found/compared in previous part) the height of OP so u can simplify the equation to tht I have already stated.U cud use the sin method to help u further and make it more simple but the actual idea of using sin is just to make it more simpler since the height comparison can be construed by ......(as stated abv)i know that. but i dont understand where is their height?
lossing 5-7 Mostly!how much marks are you guys getting in P1's?
nOpeO.o5
^ is this zero significant?
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