Maths, Addmaths and Statistics: Post your doubts here!

[***amd***]

Yes. Its OA + OB.

can u upload the figure?

 

[exploded diper]

This as well.
***amd***

as u know retartdation is -2
let x be the unknown speed at 15
so -2=x-50/15-0
through the formula of the gradient or acceleration ...which ever u like..

 

[Awesome12]

no that is given in the question

its simple maaaan!
3rt of 5 is givenm, and 3rt of 1000 is 10. do u need time even for this?

Alright, I didn't know it was given

 

[funky brat]

as u know retartdation is -2
let x be the unknown speed at 15
so -2=x-50/15-0
through the formula of the gradient or acceleration ...which ever u like..

And the other question?

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w06_qp_1.pdf
Question 12 part c Samjha do koi. :/

 

[Dark Destination]

And the other question?

Which ones?

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w06_qp_1.pdf
Question 22 aii as well.

 

[***amd***]

This as well.
***amd***

answer is 20?

 

[funky brat]

View attachment 43659
Part b?

Dark Destination

 

[funky brat]

answer is 20?

Woh speed time wala hai mje, leave it.
Tell the other one.

 

[Dark Destination]

Dark Destination

-9+3/2 = -3

f(t) = t+3/2

Add them both up, and simplify them, and then compare with A + Bt.. to get values of A and B..

 

[exploded diper]

Woh speed time wala hai mje, leave it.
Tell the other one.

Is this the correct answer?I think its like this...

 

[funky brat]

-9+3/2 = -3

f(t) = t+3/2

Add them both up, and simplify them, and then compare with A + Bt.. to get values of A and B..

-6+t+3/2= -3+t/2
-3+t/2= A+ Bt
Now how to compare them? :/

 

[Dark Destination]

-6+t+3/2= -3+t/2
-3+t/2= A+ Bt
Now how to compare them? :/

You made an error.

See exploded dipers working, that is how you do it.

 

[era30amy]

Could someone help me with Transformation, Sets and Venn diagram and Statistics?
I am shit out of luck. ='|

 

[funky brat]

You made an error.

See exploded dipers working, that is how you do it.

This is what he has written, I guess.

 

[funky brat]

Is this the correct answer?View attachment 43661I think its like this...

I got that. Thanks.

 

[princess Anu]

for the gradient draw the tangent . mark 2 point and find gradient. i cant to dat on screen properly

But why would it be equal to the straight line 's gradient?

 

[exploded diper]

I got that. Thanks.

k

 

[Awesome12]

But why would it be equal to the straight line 's gradient?

See it would be hard to find the gradient on a curve, won't it. So the line that we draw passes through the point on a curve. Since any point on a line will have the same gradient as the gradient of the line, the curve will also have the same gradient